Hematite is an iron ore with the following composition: Fe2O3 [MW=159.70]. To make steel, carbon [At. Wt. = 12.01] in the form of coke is used to reduce Fe2O3 to iron metal [At. Wt. = 55.85] as shown below: 3 C + 2 Fe2O3 → 3 CO2 + 4 Fe How many grams of carbon are needed to produce 2,500 grams of iron? Relative to the problem the processing of 798.5 g of hematite ore produced 508.2 g of iron metal. Determine the percent yield of pure iron for this batch?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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  1. Hematite is an iron ore with the following composition: Fe2O3 [MW=159.70]. To make steel, carbon [At. Wt. = 12.01] in the form of coke is used to reduce Fe2O3 to iron metal [At. Wt. = 55.85] as shown below:

3 C + 2 Fe2O3 → 3 CO2 + 4 Fe

How many grams of carbon are needed to produce 2,500 grams of iron?

Relative to the problem the processing of 798.5 g of hematite ore produced 508.2 g of iron metal. Determine the percent yield of pure iron for this batch?

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