help with c++...paste working indented code plzz 2. Continuous of question 1. Implement operator overloading. Operator Overloading a) Implement two unary operator overload functions (-,+,!). b) Implement four arithmetic operator overload functions (+,-,*,/). c) Implement six relational operator overload functions (==,!=,>,>=,<,<=). d) Implement the insertion operator overload function (<<). e) Implement the extraction operator overload function (>>). f) Implement the subscript operator overload function ([]). Make sure that each function is optimally overloaded for its purpose. (pick between member, non-member, friend as appropriate) Notes Add Rational Numbers Given a/b + c/d: Step 1: Find the LCM of b and d. Step 2: Create a new Rational Number: ((a*(LCM/b) + (c*(LCM/d)) / LCM. Step 3: Reduce the new Rational Number from step 2. Step 4: Return the new Rational Number. Subtract Rational Numbers Given a/b - c/d: Step 1: Find the LCM of b and d. Step 2: Create a new Rational Number: ((a*(LCM/b) - (c*(LCM/d)) / LCM. Step 3: Reduce the new Rational Number from step 2 Step 4: Return the new Rational Number. Multiply Rational Numbers Given a/b * c/d: Step 1: Create a new Rational Number: (a*c) / (b*d). Step 2: Return the new Rational Number. Divide Rational Numbers Given a/b / c/d: Step 1: Create a new Rational Number: (a*d) / (b*c). Step 2: Return the new Rational Number. Compare Rational Numbers: greater than Determine if a/b > c/d: Step 1: Find the LCM of b and d. Step 2: If (a* (LCM/b) > (c* (LCM/d) return true, otherwise false. Compare Rational Numbers: less than Determine if a/b < c/d: Step 1: Find the LCM of b and d Step 2: If (a*(LCM/b) < (c* (LCM/d) return true, otherwise false. Use following main function to test your program. (have to use this main function) int main ~ cout << endl; RatNum r1(1,2), r2(1,6), r3(2,5); // test operator overloads cout << "\nInput/Output Stream Operators: " << endi; RatNum r4; cout << "Enter a rational number: " cin >> r4: cout << r4 << endi; cout << "Negation Operation: " << endi; cout <<-r4 << endl: // test arithmetic overloads cout << "\nArithmetic Operators: " < " << r6 << "? " << (r5>r6) << endl; cout << r5 << " < " << r6 << "? " << (r5
help with c++...paste working indented code plzz
2. Continuous of question 1. Implement operator overloading.
Operator Overloading
a) Implement two unary operator overload functions (-,+,!).
b) Implement four arithmetic operator overload functions (+,-,*,/).
c) Implement six relational operator overload functions (==,!=,>,>=,<,<=). d) Implement the insertion operator overload function (<<).
e) Implement the extraction operator overload function (>>).
f) Implement the subscript operator overload function ([]).
Make sure that each function is optimally overloaded for its purpose. (pick between member, non-member, friend as appropriate)
Notes
Add Rational Numbers
Given a/b + c/d:
Step 1: Find the LCM of b and d.
Step 2: Create a new Rational Number: ((a*(LCM/b) + (c*(LCM/d)) / LCM. Step 3: Reduce the new Rational Number from step 2.
Step 4: Return the new Rational Number.
Subtract Rational Numbers
Given a/b - c/d:
Step 1: Find the LCM of b and d.
Step 2: Create a new Rational Number: ((a*(LCM/b) - (c*(LCM/d)) / LCM.
Step 3: Reduce the new Rational Number from step 2
Step 4: Return the new Rational Number.
Multiply Rational Numbers
Given a/b * c/d:
Step 1: Create a new Rational Number: (a*c) / (b*d).
Step 2: Return the new Rational Number.
Divide Rational Numbers
Given a/b / c/d:
Step 1: Create a new Rational Number: (a*d) / (b*c).
Step 2: Return the new Rational Number.
Compare Rational Numbers: greater than
Determine if a/b > c/d:
Step 1: Find the LCM of b and d.
Step 2: If (a* (LCM/b) > (c* (LCM/d) return true, otherwise false.
Compare Rational Numbers: less than
Determine if a/b < c/d:
Step 1: Find the LCM of b and d
Step 2: If (a*(LCM/b) < (c* (LCM/d) return true, otherwise false.
Use following main function to test your program. (have to use this main function)
int main ~
cout << endl;
RatNum r1(1,2), r2(1,6), r3(2,5);
// test operator overloads
cout << "\nInput/Output Stream Operators: " << endi;
RatNum r4;
cout << "Enter a rational number: "
cin >> r4:
cout << r4 << endi;
cout << "Negation Operation: " << endi;
cout <<-r4 << endl:
// test arithmetic overloads
cout << "\nArithmetic Operators: " <<endl;
RatNum r5 = r1 + r2;
cout << r1 <<"+ "< r2 << "= "'<< r5 << endI;
RatNum r6 = r1 - r2;
cout << r1 <<"-"<< r2 << " = "«< r6 << endi:
RatNum r7 =r1 * r2l;
cout << r1 <<" «< r2 << "= " << r7 << endI;
RatNum r8 = r1 / r2;
cout<<r1<<"/"<<r2<< "="<<r8<<endl;
// test arithmetic operation chaining
cout << "\nArithmetic Chaining: " << endl;
RatNum r9 = r5 + r6 - r7 * r8;
cout<<r5<< "+"<<r6<<"-"<<r7<<"*"<<r8<<"="<<r9<<endl;
// test relational operator overload
cout << "\nRelational Operators: " << endl;
cout << r5 << " == " << r6 << "? " << (r5==r6) << endl; cout << r5 << " != " << r6 << "? " << (r5!=r6) << endl; cout << r5 << " > " << r6 << "? " << (r5>r6) << endl; cout << r5 << " < " << r6 << "? " << (r5<r6) << endl;
// test subscript overload
cout << "\nSubscript Operator: " << endl;
cout << r5 << " num=" << r5[1] << " den=" << r5[2] << endl; cout << endl;
return 0;
}
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 1 images
