Hello,On this question I get eigenvalues of .07 and .11 from the quadratic equation, despite .07 and 0.11 not being the product of .77. Because the eigenvalues are so small, the subtraction (A-I lambda) is positive, such as .49. Because of this, there is only one negative to work with in the matrix, and the second column, second row index cannot be canceled out to zero using a multiple of the first row. Could point out what I'm doing wrong on the first part of this question?Thanks S. Denote the owl and tat population ink (in months) by Xx=aot timeparticwar regionwhere Ok s the number of owls in there gu on, and Rk s the neumber of rats (in qhe thouwands). SupreOkes- 0.60k +0.SRu and Ricay= p Ok+1.2RkOk + 1.2Rka predwioh parameter.claned form vector equation that models the owl and ratwhereisa) Findpopwations for p=0.1.6) Upadate your mobel goven that the iwtial population of owls s400 and of Pats is 200 ,000.c) Compute the lim Xx and explown what is happening long-term with1-11 (A -.111)d= 3+1 102-1 109the populations of owls and rats...1 1-2[-1 1-091 1.021odet (A-XI)= O|.G-A S- (.6-))(1.2 -) +05 = 0:x -D\ +1.22-.1 1.2-)4.8±/3.24 - 4(4)(1.22)1= 1.8 J3.24-4(. ?)2(1)1- 1-8±-1.64A= 1-8 ±S.16-X-18入.17-0X=.09t .02

Given- xk = OkRkwhere Ok is the number of owls in the region andRk is the number of rats in the…

Hello, On this question I get eigenvalues of .07 and .11 from the quadratic equation, despite .07 and 0.11 not being the product of .77. Because the eigenvalues are so small, the subtraction (A-I lambda) is positive, such as .49. Because of this, there is only one negative to work with in the matrix, and the second column, second row index cannot be canceled out to zero using a multiple of the first row. Could point out what I'm doing wrong on the first part of this question? Thanks

Hello, On this question I get eigenvalues of .07 and .11 from the quadratic equation, despite .07 and 0.11 not being the product of .77. Because the eigenvalues are so small, the subtraction (A-I lambda) is positive, such as .49. Because of this, there is only one negative to work with in the matrix, and the second column, second row index cannot be canceled out to zero using a multiple of the first row. Could point out what I'm doing wrong on the first part of this question? Thanks

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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