For the following matrices A, compute A is a 3x3 matrix, having eigenvalues -12-2,and-4. A= -3.8 1-4 -1.6 -28 04 -0.8 0.4 -3.6 Find their corresponding eigen vectors V₁, V₂, V3 Defined by matrix Let V=/V₁ V₂ V₂ => (**) example V ₁AV = (-100 مانا- 0-20 00-4/ A=VrV¹ eft = Vent vi VI O C²² 00 e-ut
For the following matrices A, compute A is a 3x3 matrix, having eigenvalues -12-2,and-4. A= -3.8 1-4 -1.6 -28 04 -0.8 0.4 -3.6 Find their corresponding eigen vectors V₁, V₂, V3 Defined by matrix Let V=/V₁ V₂ V₂ => (**) example V ₁AV = (-100 مانا- 0-20 00-4/ A=VrV¹ eft = Vent vi VI O C²² 00 e-ut
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
Transcribed Image Text:For the following matrices A, compute At
A is a 3x3 matrix, having eigenvalues
-12-2, and-4-
A=
1-3-8
1-4 -1.6
-28
0.4
-0.8 0-4 -3.6
Find their corresponding eigen vectors
V₁, V₂, V3
مانا -
Defined by matrix > Let V=/V₁ V₂ V3
(5)
example,
V ₁AV = (-100
0-20
00-4/
A=VrV¹
eft = Vent vi
At
v/et
o eat
e-4t,
Expert Solution
Step 1
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Solved in 4 steps with 1 images
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Follow-up Question
It's unclear to me how the eigenvectors were calculated.
And the final value of eAt is also unclear to me..
![Step 2
eigen vector are
eat
1- ^ 76² ^ = 702
veît
(using
é
Calculated incorrect.
-2.8
-2-8
-0.8
eigenvector corresponding to a = -1 be m
[:]
e-2t
[
1.५ -1.6
1.4
-1.6
-2.6
0.4
Row- reduction
[²
-1/₂
m=
thia
-1.8 1.4
JJ
0.4
-0.8
1.4
0=Eul
7/1. = 11e
[:]
O
eigenvector corresponding to a = = 2 ben
lue
)
-1.6
ES-BO [:]
- २.४ 24
-1.6
-1.6
m₂
[618]
m3
Eut
Let m₂ = 1
n2
из
[8] - [%]](https://content.bartleby.com/qna-images/question/19556b7c-c5b6-4b4d-b523-18b6eba0d2d2/6afa27c8-43e4-408b-b6d6-ffd07b6c01fe/xx897y_processed.jpeg)
Transcribed Image Text:Step 2
eigen vector are
eat
1- ^ 76² ^ = 702
veît
(using
é
Calculated incorrect.
-2.8
-2-8
-0.8
eigenvector corresponding to a = -1 be m
[:]
e-2t
[
1.५ -1.6
1.4
-1.6
-2.6
0.4
Row- reduction
[²
-1/₂
m=
thia
-1.8 1.4
JJ
0.4
-0.8
1.4
0=Eul
7/1. = 11e
[:]
O
eigenvector corresponding to a = = 2 ben
lue
)
-1.6
ES-BO [:]
- २.४ 24
-1.6
-1.6
m₂
[618]
m3
Eut
Let m₂ = 1
n2
из
[8] - [%]
![let n₂ = 1
₂ = -4
31=-4
[=4
Similarly eigenvector corresponding 2 = -4 be p
P = [ 1 ]
V =
VA
=
Adjv
12
det V
=
O
Adj V
det V =
vy
V
=
Adj V
A
-5
1
51/2-1/2
1/2₂
9
det V = 5/2
-1
1/2 (-5)
2
-5
1
T
5
1/2
-1/₂
1/2
+4+1
50
1/2 1/2
-1/2 2
2 2
-2/5 1/5 1/5
215
-1/5 4/5](https://content.bartleby.com/qna-images/question/19556b7c-c5b6-4b4d-b523-18b6eba0d2d2/6afa27c8-43e4-408b-b6d6-ffd07b6c01fe/yatx0ju_processed.jpeg)
Transcribed Image Text:let n₂ = 1
₂ = -4
31=-4
[=4
Similarly eigenvector corresponding 2 = -4 be p
P = [ 1 ]
V =
VA
=
Adjv
12
det V
=
O
Adj V
det V =
vy
V
=
Adj V
A
-5
1
51/2-1/2
1/2₂
9
det V = 5/2
-1
1/2 (-5)
2
-5
1
T
5
1/2
-1/₂
1/2
+4+1
50
1/2 1/2
-1/2 2
2 2
-2/5 1/5 1/5
215
-1/5 4/5
Solution
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