Heating Curve Problems mp = 5.48 °C bp = 80.1 °C c (1) = 1.74 J/g°C c (g) = 1.04 J/g°C AHfus = 9.90 KJ/mol For H2O: mp = 0 °C bp = 100 °C c (ice) = 2.06 J/g°C c (water) = 4.184 J/g°C c (steam) = 2.03 J/g°C AHfus = 6.02 KJ/mol For CH6: AHvap = 30.77 KJ/mol AHvap = 40.79 KJ/mol Q = mcAT Q = nAHfus Q = nAHvap (used with temperature changes) (used during fusion or solidification) (used during vaporization or condensing) 1. Use the information above and draw a heating curve for water. 2. How much heat (in kJ) is needed to change 4.5 g of ice at -20.°C to steam at 120.°C?

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Can you please solve question 2 on the attached document; showing step by step solution.

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Heating Curve Problems
mp = 0 °C
bp = 100 °C
c (ice) = 2.06 J/g°C
c (water) = 4.184 J/g°C
c (steam) = 2.03 J/g°C
AHfus = 6.02 KJ/mol
mp = 5.48 °C
bp = 80.1 °C
c (1) = 1.74 J/g°C
c (g) = 1.04 J/g°C
AHfus = 9.90 KJ/mol
For H2O:
For C,H6:
AHvap = 30.77 KJ/mol
AHvap = 40.79 KJ/mol
Q = mcAT
Q = nAHfus
Q = nAHva
(used with temperature changes)
(used during fusion or solidification)
(used during vaporization or condensing)
Vap
1. Use the information above and draw a heating curve for water.
2. How much heat (in kJ) is needed to change 4.5 g of ice at -20.°C to steam at 120.°C?
Transcribed Image Text:Heating Curve Problems mp = 0 °C bp = 100 °C c (ice) = 2.06 J/g°C c (water) = 4.184 J/g°C c (steam) = 2.03 J/g°C AHfus = 6.02 KJ/mol mp = 5.48 °C bp = 80.1 °C c (1) = 1.74 J/g°C c (g) = 1.04 J/g°C AHfus = 9.90 KJ/mol For H2O: For C,H6: AHvap = 30.77 KJ/mol AHvap = 40.79 KJ/mol Q = mcAT Q = nAHfus Q = nAHva (used with temperature changes) (used during fusion or solidification) (used during vaporization or condensing) Vap 1. Use the information above and draw a heating curve for water. 2. How much heat (in kJ) is needed to change 4.5 g of ice at -20.°C to steam at 120.°C?
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