Please help with trial 1 )et:eceunts ofChem 105-OnlineInitial Temperature (T₁)Final Temperature (T₂)Part A: Heat of FusionChange in TemperatureMass of cupMass of cup + waterMass of water (mw) calculatedMass of cup + water + melted iceMass of ice (mi) calculatedHeat absorbed by ice water as temperatureequilibrium is established (Q₁)Total heat energy lost by water (Q₂)Heat absorbed by ice as it melted (Q3)Heat of Fusion for water in this experimentAverage Heat of FusionPercent Error for Heat of Vaporization (True AHfus =334J/g)Part A Time(s) (Trial 1)0306090120150180210240270300330360390420450Temperature (Trial 1)ISOC9°cтос6%6°CTrial 115⁰c6°c2.30g148.83g161.92gPart A Time(s) (Trial 2)0306090120150180210240270300330360390420450Trial 2Temperature (Trial 2)

Initial temperature, T1=15 oC Final temperature, T2=9 oC Mass of cup=2.30 g Mass of cup +…

Answered: Heat of Fusion

Science

Chemistry

Heat of Fusion

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Crystal Structures

Solids are present all around us. They have different properties and applications. Diamond and graphite are two well-known solids. Diamond is the hardest material in the world and is used in making jewelry. Graphite on the other hand is soft. The lead of your pencil is graphite. Why are they so different in appearance and properties despite the fact they are chemically the same? Both are allotropes of carbon. The answer lies in the structure, the way constituent particles are arranged in the solids.

Question

Please help with trial 1

)
et:
e
ce
unt
s of
Chem 105-Online
Initial Temperature (T₁)
Final Temperature (T₂)
Part A: Heat of Fusion
Change in Temperature
Mass of cup
Mass of cup + water
Mass of water (mw) calculated
Mass of cup + water + melted ice
Mass of ice (mi) calculated
Heat absorbed by ice water as temperature
equilibrium is established (Q₁)
Total heat energy lost by water (Q₂)
Heat absorbed by ice as it melted (Q3)
Heat of Fusion for water in this experiment
Average Heat of Fusion
Percent Error for Heat of Vaporization (True AHfus =
334J/g)
Part A Time(s) (Trial 1)
0
30
60
90
120
150
180
210
240
270
300
330
360
390
420
450
Temperature (Trial 1)
ISOC
9°c
тос
6%
6°C
Trial 1
15⁰c
6°c
2.30g
148.83g
161.92g
Part A Time(s) (Trial 2)
0
30
60
90
120
150
180
210
240
270
300
330
360
390
420
450
Trial 2
Temperature (Trial 2)

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