he Sun subtends an angle of 0.533° at a distance of 1 astronomical unit, which is 1.496 ✕ 1011 m, the average Sun–Ea
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Q: The Sun subtends an angle of 0.533° at a distance of 1 astronomical unit, which is 1.496 ✕ 1011 m,…
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A: a) The radius of the curvature, 1q+1p=2RR=2p·qp+qR=2×1×(6)1-(6)R=2.4cm
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- You have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is 1.92m and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 3.16m, what is the focal length of the mirror? The magnification equation and the sign convention for q imply that real images of real objects are always inverted (if both p and q are positive, m is negative); virtual images of real objects are always upright (if p is positive and q is negative, m is positive). Keeping the signs of p and q straight in your mind is the most challenging aspect of mirrors (and lenses). Fortunately, table 23.2 summarizes when p and q are positive and when they are negative.A convex mirror has the focal length with magnitude equal to 0.375 m. An object is place 0.164 m in front of the mirror. What is the magnification of the image (answer sign and magnitude)? PLEASE ANSWER USING 3 SIG FIG AND IN SCIENTIFIC NOTATION USING E ONLYA concave mirror has a focal length of 40.6 cm. The distance between an object and its image is 74.8 cm. Find (a) the object and (b) image distances, assuming that the object lies beyond the center of curvature and (c) the object and (d) image distances, assuming that the object lies between the focal point and the mirror.
- You have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is 0.68m and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 3.37m, what is the focal length of the mirror? h B Al C h' The magnification equation and the sign convention for q imply that real images of real objects are always inverted (if both p and q are positive, m is negative); virtual images of real objects are always upright (if p is positive and q is negative, m is positive). Keeping the signs of p and q straight in your mind is the most challenging aspect of mirrors (and lenses). Fortunately, table 23.2 summarizes when p and q are positive and when they are negative.Some telephoto cameras use a mirror rather than a lens to magnify distant objects. What radius of curvature R, in meters, does the mirror need to have to replace a 550 mm focal length telephoto lens?You have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is 0.63m and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 4.2m, what is the focal length of the mirror?
- A converging lens such as a magnifying glass has a radius of curvature of 14.6 cm. A letter in a book under this magnifying glass appears 3 times larger than its actual size. If the image is upright. how many centimeters is the book from, the magnifying glass? Please round your answer to one decimal place.The equation connecting s, p, and f for a simple lens can be employed for spherical mirrors, too. A concave mirror with a focal length of 4 cm forms an image of a small object placed 13 cm in front of the mirror. Where will this image be located? (For spherical mirrors, positive p means the image is on the same side of the mirror as the object.)In front of a spherical concave mirror of radius 27.5 cm, you position an object of height 2.80 cm somewhere along the principal axis. The resultant image has a height of 11.20 cm. How far from the mirror is the object located? 22.4 cm 10.3 cm 17.2 cm 6.9 cm
- The equation connecting s, p, and f for a simple lens can be employed for spherical mirrors, too. A concave mirror with a focal length of 9 cm forms an image of a small object placed 15 cm in front of the mirror. Where will this image be located? (For spherical mirrors, positive p means the image is on the same side of the mirror as the object.)p = cmA concave mirror has a focal length of 39.3 cm. The distance between an object and its image is 66.8 cm. Find (a) the object and (b) image distances, assuming that the object lies beyond the center of curvature and (c) the object and (d) image distances, assuming that the object lies between the focal point and the mirror. (a) Number i (b) Number (c) Number (d) Number MI MI Mi Units Units Units UnitsIn front of a spherical convex mirror of radius 49.2 cm, you position an object of height 4.42 cm somewhere along the principal axis. The resultant image has a height of 1.77 cm. How far from the mirror is the object located?