A concave mirror has a focal length of 39.3 cm. The distance between an object and its image is 66.8 cm. Find (a) the object and (b) image distances, assuming that the object lies beyond the center of curvature and (c) the object and (d) image distances, assuming that the object lies between the focal point and the mirror.
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- A concave mirror has a focal length of 40.6 cm. The distance between an object and its image is 74.8 cm. Find (a) the object and (b) image distances, assuming that the object lies beyond the center of curvature and (c) the object and (d) image distances, assuming that the object lies between the focal point and the mirror.A convex mirror has a focal length of magnitude 6.38 cm. (a) If the image is virtual, what is the object location for which the magnitude of the image distance is one third the magnitude of the object distance? (Enter distance in cm from the front of the mirror. If the image is real, enter NONE.) cm(b) Find the magnification of the image.Problem 7: An object 1.55 cm high is held 2.8 cm from a person’s cornea, and its reflected image is measured to be 0.165 cm high. Part (a) What is the magnification? Part (b) What is the image distance in cm? Part (c) Find the radius of curvature in cm of the convex mirror formed by the cornea.
- You want to use a converging mirror to magnify an object. (a) Where do you need to place the object in order to get a magnified image? (b) The mirror has a focal length of 19 cm. You get an upright image that is 2.4x the height of the object. How far from the mirror did you place the object? do = cm (c) What is the image distance for this mirror? Include the sign (±) in your answer. d₁ = cm (d) Is the image real or virtual?An object 1.6 cm high is held 3.15 cm from a person’s cornea, and its reflected image is measured to be 0.175 cm high. Part (a) What is the magnification? Part (b) What is the image distance in cm? Part (c) Find the radius of curvature in cm of the convex mirror formed by the cornea.3. An elevator starts from the third floor and moves downward. The v-t graph of a person riding the elevator is given below: t₁ = 0.9 s,t₂ = 1.9 s, t3 = 4.5 s, tv = 7.7 s, v = -1.0 m/s Velocity (m/s) (a) Draw FBD for the person riding the elevator for following cases: Speeding Constant moving Time (s) Slowing (b) What is the apparent weight (in N) of a 50.0 kg person when he/she is slowing down? (Use g = 10 N/kg). Speeding Constant moving Slowing
- An object of 2 cm tall is placed 1cm in front of a convex mirror of focal length of 2 cm. (a) Use ray tracing to find the image. (b) Use the mirror equation to find the image distance and compare it to your ray tracing and find the percentage error.An object 1.7 cm high is held 2.75 cm from a person’s cornea, and its reflected image is measured to be 0.171 cm high. Part (a) What is the magnification? Part (b) What is the image distance in cm? Part (c) Find the radius of curvature in cm of the convex mirror formed by the cornea.An object located 1.21 cm in front of a spherical mirror forms an image located 10.6 cm behind the mirror. (a) What is the mirror's radius of curvature (in cm)? cm (b) What is the magnification of the image? Need Help? Read It
- A concave mirror has a focal length of 31.4 cm. The distance between an object and its image is 56.2 cm. Find (a) the object and (b) image distances, assuming that the object lies beyond the center of curvature and (c) the object and (d) image distances, assuming that the object lies between the focal point and the mirror. (a) Number (b) Number (c) Number i (d) Number i Units Units Units UnitsWhen viewed in a spherical mirror, the image of a setting sun is a virtual image. The image lies 11 cm behind the mirror. (a) What is the focal length of the mirror? (b) What is the radius of curvature of the mirror?A virtual image is formed 24.5 cm from a concave mirror having a radius of curvature of 39.5 cm. (a) Find the position of the object. cm in front of the mirror (b) What is the magnification of the mirror?