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he heat capacities of nitrogen gas at constant volumes were measured at the ollowing temperatures (David Ball, Physical Chemistry 4th edition pg 65): Cv (J mol1 K-1) 300 20.8 400 20.9 500 21.2 600 21.8 700 22.4 800 23.1 900 23.7 1000 24.3 1100 24.9

he heat capacities of nitrogen gas at constant volumes were measured at the ollowing temperatures (David Ball, Physical Chemistry 4th edition pg 65): Cv (J mol1 K-1) 300 20.8 400 20.9 500 21.2 600 21.8 700 22.4 800 23.1 900 23.7 1000 24.3 1100 24.9

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The heat capacities of nitrogen gas at constant volumes were measured at the following temperatures (David Ball, Physical Chemistry 4th edition pg 65): Cv (J mol1 K-1) 300 20.8 400 20.9 500 21.2 600 21.8 700 22.4 800 23.1 900 23.7 1000 24.3 1100 24.9 a. graph C vs T then using excel what polynomial trendline is needed to get a fit of R? = 0.999? Using this polynomial what would be the heat of a process heating 3.189 mol of nitrogen gas from 461 K to 917 K? b. Fit the data above using what many texts do: Cy = A + BT +C/T² . This is something likely to be new to you using excel. You will have to have a column for I and an adjacent column for 1/T?. Then a column for Cy. Go into Data analysis under tools and choose regression. Enter in your Cv column for y and select BOTH the T and 1/T2 columns for your x values. Choose a square in your excel sheet to place the answers. The A, B and C values will be in there! What would the heat of the process from part a be now if using this C(T)?
Transcribed Image Text:The heat capacities of nitrogen gas at constant volumes were measured at the following temperatures (David Ball, Physical Chemistry 4th edition pg 65): Cv (J mol1 K-1) 300 20.8 400 20.9 500 21.2 600 21.8 700 22.4 800 23.1 900 23.7 1000 24.3 1100 24.9 a. graph C vs T then using excel what polynomial trendline is needed to get a fit of R? = 0.999? Using this polynomial what would be the heat of a process heating 3.189 mol of nitrogen gas from 461 K to 917 K? b. Fit the data above using what many texts do: Cy = A + BT +C/T² . This is something likely to be new to you using excel. You will have to have a column for I and an adjacent column for 1/T?. Then a column for Cy. Go into Data analysis under tools and choose regression. Enter in your Cv column for y and select BOTH the T and 1/T2 columns for your x values. Choose a square in your excel sheet to place the answers. The A, B and C values will be in there! What would the heat of the process from part a be now if using this C(T)?
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