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Have the student use the infomration obtain regarding the USA population to determine the “Expected” frequency and counts as well as having them  to analyze the data and provide phenotype, genotype and allele frequencies plus the perform chi-square analyses. Have the student to complete every single empty square. For frequencies, (O-E)2 /E and x^2 round to two decimal places. Use whole numbers for counts

Have the student use the infomration obtain regarding the USA population to determine the “Expected” frequency and counts as well as having them  to analyze the data and provide phenotype, genotype and allele frequencies plus the perform chi-square analyses. Have the student to complete every single empty square. For frequencies, (O-E)2 /E and x^2 round to two decimal places. Use whole numbers for counts

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Have the student use the infomration obtain regarding the USA population to determine the “Expected” frequency and counts as well as having them  to analyze the data and provide phenotype, genotype and allele frequencies plus the perform chi-square analyses. Have the student to complete every single empty square. For frequencies, (O-E)2
/E and x^2 round to two decimal places. Use whole numbers for counts… people are counted in whole numbers! 

I. Test S = Sodium benzoate: BIO 340 USA II. Test T = Phenylthiocarbamide (PTC) TASTERS (p² + 2pq) # 280 N.A. III. Test U = Thiourea 1. 2. TASTERS (p²+2pq) # 225 N.A. BIO 340 USA 3. Observed BIO 340 Counts Observed BIO 340 Frequency Expected Frequency Expected Counts (O-E)²/E 4. FREQUENCY 5. 0.25 BIO 340 USA FREQUENCY Observed BIO 340 Counts Observed BIO 340 Frequency Expected Frequency Expected Counts (O-E)²/E 0.70 TASTERS (p² + 2pq) # 230 N.A. Did you expect these results? Explain why. FREQUENCY Observed BIO 340 Counts Observed BIO 340 Frequency Expected Frequency Expected Counts (O-E)²/E NON-TASTERS (9²) # 75 N.A. SS (p²) # 20 N.A. NON-TASTERS (q²) TT (p²) FREQUENCY # 70 N.A. Ss (2pq) UU (p²) FREQUENCY NON-TASTERS (9²) Tt (2pq) FREQUENCY Uu (2pq) ALLELE FREQUENCIES p р ss (q²) 75 tt (q²) 20 Mention 3 reasons why most populations are NOT in Hardy-Weinberg equilibrium: ALLELE FREQUENCIES Р 0.45 uu (q²) 70 TOTAL 300 1 1 x² = q = TOTAL 300 ALLELE FREQUENCIES Р 9 Use the Chi-square stable, which can be found in the Chi-Square Analysis of Mendel's Data page of your online textbook as well as in the Module IV Chi-square analysis lecture, to determine whether you should reject the null hypotheses (Ho) or not. Provide your answers next to each of the compounds. Sodium benzoate Ho: Phenylthiocarbamide (PTC) Ho: Thiourea Ho: x² = How do the BIO 340 student results compare to those of previously published data from the USA population? Note: Compare the genotype/allele frequencies of each of the test papers. 1 1 9 0.55 TOTAL 300 1 1
Transcribed Image Text:I. Test S = Sodium benzoate: BIO 340 USA II. Test T = Phenylthiocarbamide (PTC) TASTERS (p² + 2pq) # 280 N.A. III. Test U = Thiourea 1. 2. TASTERS (p²+2pq) # 225 N.A. BIO 340 USA 3. Observed BIO 340 Counts Observed BIO 340 Frequency Expected Frequency Expected Counts (O-E)²/E 4. FREQUENCY 5. 0.25 BIO 340 USA FREQUENCY Observed BIO 340 Counts Observed BIO 340 Frequency Expected Frequency Expected Counts (O-E)²/E 0.70 TASTERS (p² + 2pq) # 230 N.A. Did you expect these results? Explain why. FREQUENCY Observed BIO 340 Counts Observed BIO 340 Frequency Expected Frequency Expected Counts (O-E)²/E NON-TASTERS (9²) # 75 N.A. SS (p²) # 20 N.A. NON-TASTERS (q²) TT (p²) FREQUENCY # 70 N.A. Ss (2pq) UU (p²) FREQUENCY NON-TASTERS (9²) Tt (2pq) FREQUENCY Uu (2pq) ALLELE FREQUENCIES p р ss (q²) 75 tt (q²) 20 Mention 3 reasons why most populations are NOT in Hardy-Weinberg equilibrium: ALLELE FREQUENCIES Р 0.45 uu (q²) 70 TOTAL 300 1 1 x² = q = TOTAL 300 ALLELE FREQUENCIES Р 9 Use the Chi-square stable, which can be found in the Chi-Square Analysis of Mendel's Data page of your online textbook as well as in the Module IV Chi-square analysis lecture, to determine whether you should reject the null hypotheses (Ho) or not. Provide your answers next to each of the compounds. Sodium benzoate Ho: Phenylthiocarbamide (PTC) Ho: Thiourea Ho: x² = How do the BIO 340 student results compare to those of previously published data from the USA population? Note: Compare the genotype/allele frequencies of each of the test papers. 1 1 9 0.55 TOTAL 300 1 1
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