have already asked this question twice. Please only answer this problem if you can answer explicitly the question I have. I already know how to do part of the problem and do not need help with finding the magnitudes of the torques. I need an explanation of how to determine specifically the direction of the rotation (clockwise or counterclockwise) associated with the torque. I know that if the direction is counterclockwise, then the torque is positive, and if the direction is clockwise, then the torque is negative. Problem: The body in the figure is pivoted at O. Three forces act on it: FA = 10N at point A, 8.0m from O; FB = 16N at point B, 4.0m from O; and FC = 19N at point C, 3.0m from O. What is the net torque about O? Part of the Solution: I am using the formulas: tauA = FArA sin thetaA = (10)(8.0) sin 1350; tauB = FBrB sin thetaB = (16)(4.0) sin 900 tauC = FCrC sin thetaC = (19)(3.0) sin 1600 So, I can find the magnitudes of the three torques (tauA, tauB, and tauC). Here is where I need help: I do not know how to determine the signs of the torques, that is, how to determine the direction of the rotation (clockwise or counterclockwise). Please explain what is the axis of rotation here, and how to determine the direction of the rotation (clockwise or counterclockwise) for this problem specifically and in general. I know that if the direction is counterclockwise, then the torque is positive, and if the direction is clockwise, then the torque is negative.
I have already asked this question twice. Please only answer this problem if you can answer explicitly the question I have. I already know how to do part of the problem and do not need help with finding the magnitudes of the torques. I need an explanation of how to determine specifically the direction of the rotation (clockwise or counterclockwise) associated with the torque. I know that if the direction is counterclockwise, then the torque is positive, and if the direction is clockwise, then the torque is negative.
Problem: The body in the figure is pivoted at O. Three forces act on it: FA = 10N at point A, 8.0m from O; FB = 16N at point B, 4.0m from O; and FC = 19N at point C, 3.0m from O. What is the net torque about O?
Part of the Solution: I am using the formulas: tauA = FArA sin thetaA = (10)(8.0) sin 1350; tauB = FBrB sin thetaB = (16)(4.0) sin 900
tauC = FCrC sin thetaC = (19)(3.0) sin 1600
So, I can find the magnitudes of the three torques (tauA, tauB, and tauC).
Here is where I need help: I do not know how to determine the signs of the torques, that is, how to determine the direction of the rotation (clockwise or counterclockwise). Please explain what is the axis of rotation here, and how to determine the direction of the rotation (clockwise or counterclockwise) for this problem specifically and in general. I know that if the direction is counterclockwise, then the torque is positive, and if the direction is clockwise, then the torque is negative.
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