H3C-C=C-CH3 H3C Na, NH3 CH3 HÌNH, H3C Draw curved arrows to show the movement of electrons in this step of the mechanism. H3C CH3 H CH3 :NH₂

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Transcription and Explanation for Educational Website

#### Chemical Reaction Overview
This image represents a chemical reaction where 2-butyne (H₃C-C≡C-CH₃) is converted to 2-butene (H₃C-CH=CH-CH₃) using sodium (Na) in liquid ammonia (NH₃) as the reagent.

#### Reaction Mechanism and Electron Movement
Below the main reaction, there is a detailed depiction of one step in the reaction mechanism showing potential electron movement. The instructions prompt the viewer to draw curved arrows to denote electron flow during this step. Here is a breakdown of the displayed step:

1. **Left Side:** 
   - The structure shows a methylacetylene derivative (H₃C-C=C-CH₃) with an unbonded electron pair on a carbon atom, represented by two dots.
   - Ammonia (NH₃) is also depicted with nitrogen's lone pair of electrons explicitly shown.

2. **Right Side:** 
   - The resulting structure shows the partial hydrogenation of the alkyne, forming an alkene (H₃C-CH=CH-CH₂) with an anionic amide ion (NH₂⁻), indicated with a pair of dots and a negative charge.

#### Instructions:
- Participants are encouraged to draw curved arrows to illustrate the movement of electrons, signifying how bonds are broken and formed. The arrows typically start from the electron pair or bond being broken and point towards the atom or bond being formed.

This detailed analysis helps in understanding the reaction mechanism, particularly in visualizing electron movement, which is crucial for mastering organic chemistry concepts.
Transcribed Image Text:### Transcription and Explanation for Educational Website #### Chemical Reaction Overview This image represents a chemical reaction where 2-butyne (H₃C-C≡C-CH₃) is converted to 2-butene (H₃C-CH=CH-CH₃) using sodium (Na) in liquid ammonia (NH₃) as the reagent. #### Reaction Mechanism and Electron Movement Below the main reaction, there is a detailed depiction of one step in the reaction mechanism showing potential electron movement. The instructions prompt the viewer to draw curved arrows to denote electron flow during this step. Here is a breakdown of the displayed step: 1. **Left Side:** - The structure shows a methylacetylene derivative (H₃C-C=C-CH₃) with an unbonded electron pair on a carbon atom, represented by two dots. - Ammonia (NH₃) is also depicted with nitrogen's lone pair of electrons explicitly shown. 2. **Right Side:** - The resulting structure shows the partial hydrogenation of the alkyne, forming an alkene (H₃C-CH=CH-CH₂) with an anionic amide ion (NH₂⁻), indicated with a pair of dots and a negative charge. #### Instructions: - Participants are encouraged to draw curved arrows to illustrate the movement of electrons, signifying how bonds are broken and formed. The arrows typically start from the electron pair or bond being broken and point towards the atom or bond being formed. This detailed analysis helps in understanding the reaction mechanism, particularly in visualizing electron movement, which is crucial for mastering organic chemistry concepts.
**Transcription for Educational Website:**

### Chemical Reaction Description:

**Reactants and Products:**

- **Reactant:** 
  - Structure: H\(_3\)C-C≡C-CH\(_3\)
- **Reagents:** 
  - Sodium (Na), Ammonia (NH\(_3\))
- **Product:** 
  - Structure: H\(_3\)C-CH=CH-CH\(_3\)

### Mechanism Step:

- **Instruction:** 
  - Draw curved arrows to show the movement of electrons in this step of the mechanism.

**Diagram Explanation:**

1. **Left Structure:**
   - Reactant: Sodium radical (Na•)
   - Alkyne: H\(_3\)C-C≡C-CH\(_3\) with a single electron on the second carbon.

2. **Transformation:** 
   - The alkyne is transformed into an alkene with the sodium radical engaging in the reaction.

3. **Right Structure:**
   - Resulting Structure: H\(_3\)C-CH=CH-CH\(_3\) with a lone pair on the adjacent carbon.
   - Sodium ion (Na⁺) is shown on the right side of the structure indicating it has lost one electron.

### Purpose:

This step demonstrates an electron transfer process within the reaction mechanism, showcasing electron movement from the sodium radical to the alkyne, resulting in the formation of an alkene and a sodium ion. 

### Key Concept:

- **Electron Transfer:** Curved arrows should be used to illustrate the electron flow from the metal to the organic substrate, highlighting the reduction of the alkyne.
Transcribed Image Text:**Transcription for Educational Website:** ### Chemical Reaction Description: **Reactants and Products:** - **Reactant:** - Structure: H\(_3\)C-C≡C-CH\(_3\) - **Reagents:** - Sodium (Na), Ammonia (NH\(_3\)) - **Product:** - Structure: H\(_3\)C-CH=CH-CH\(_3\) ### Mechanism Step: - **Instruction:** - Draw curved arrows to show the movement of electrons in this step of the mechanism. **Diagram Explanation:** 1. **Left Structure:** - Reactant: Sodium radical (Na•) - Alkyne: H\(_3\)C-C≡C-CH\(_3\) with a single electron on the second carbon. 2. **Transformation:** - The alkyne is transformed into an alkene with the sodium radical engaging in the reaction. 3. **Right Structure:** - Resulting Structure: H\(_3\)C-CH=CH-CH\(_3\) with a lone pair on the adjacent carbon. - Sodium ion (Na⁺) is shown on the right side of the structure indicating it has lost one electron. ### Purpose: This step demonstrates an electron transfer process within the reaction mechanism, showcasing electron movement from the sodium radical to the alkyne, resulting in the formation of an alkene and a sodium ion. ### Key Concept: - **Electron Transfer:** Curved arrows should be used to illustrate the electron flow from the metal to the organic substrate, highlighting the reduction of the alkyne.
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