H2O + CH 3 COOC_2 H_5 H_3 COOH +C_2 H_5 OH In an experiment where this equilibium is investigated, 5 mL of solution (2.5 mL HCl+2 mL ethanol+0.5 mL acetic acid) is titrated with NaOH. What will be the reaction occuring in titration? Is ethanol gonna undergo a reverse reaction to form the reactants?

Fundamentals Of Analytical Chemistry
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Chapter14: Principles Of Neutralization Titrations
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H_2 O + CH 3 COOC_2 H_5= H_3 COOH +C_2 H_5 OH In an experiment where this equilibium is
investigated, 5 mL of solution (2.5 mL HCl+2 mL ethanol+0.5 mL acetic acid) is titrated with NaOH. What
will be the reaction occuring in titration? Is ethanol gonna undergo a reverse reaction to form the
reactants?
Transcribed Image Text:H_2 O + CH 3 COOC_2 H_5= H_3 COOH +C_2 H_5 OH In an experiment where this equilibium is investigated, 5 mL of solution (2.5 mL HCl+2 mL ethanol+0.5 mL acetic acid) is titrated with NaOH. What will be the reaction occuring in titration? Is ethanol gonna undergo a reverse reaction to form the reactants?
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