H2(g) + Cl2(g) ----> 2 HClg) Use the following conversions: 1 mol = MW in g (2 d.p.) = 22.414 L How many grams of HCI (MW = 36.46 g HCI) will form from 42.5 L of Cl2 gas (MW = 70.90 g Cl2)?(Express as 'g HCI') 3._ 5. 1. 42.5 L C12 x- 2. 7. 4. 6. 1.--- 2.-- 3.-- 4. _--- 5.___
H2(g) + Cl2(g) ----> 2 HClg) Use the following conversions: 1 mol = MW in g (2 d.p.) = 22.414 L How many grams of HCI (MW = 36.46 g HCI) will form from 42.5 L of Cl2 gas (MW = 70.90 g Cl2)?(Express as 'g HCI') 3._ 5. 1. 42.5 L C12 x- 2. 7. 4. 6. 1.--- 2.-- 3.-- 4. _--- 5.___
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chemical Reaction Summary:**
\[ \text{H}_2(g) + \text{Cl}_2(g) \rightarrow 2 \text{HCl}(g) \]
**Conversions Used:**
- 1 mol = MW in g (to 2 decimal places) = 22.414 L
**Problem Statement:**
Determine how many grams of HCl (with MW = 36.46 g HCl) will be produced from 42.5 L of Cl\(_2\) gas (MW = 70.90 g Cl\(_2\)). Express the answer as 'g HCl'.
**Calculation Steps:**
\[ 42.5 \, \text{L Cl}_2 \times \frac{1. \, \_\_\_\_}{2. \, \_\_\_\_} \times \frac{3. \, \_\_\_\_}{4. \, \_\_\_\_} \times \frac{5. \, \_\_\_\_}{6. \, \_\_\_\_} = 7. \, \_\_\_\_ \]
**Calculation Details:**
1. **Conversion Factor 1: \_\_\_**
2. **Conversion Factor 2: \_\_\_**
3. **Conversion Factor 3: \_\_\_**
4. **Conversion Factor 4: \_\_\_**
5. **Conversion Factor 5: \_\_\_**
**Solution Space for Calculations:**
- Box 1: \_\_\_
- Box 2: \_\_\_
- Box 3: \_\_\_
- Box 4: \_\_\_
- Box 5: \_\_\_
Fill in each step with appropriate conversion factors and calculations to solve the problem.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec1aed6b-83ca-4bd8-a12d-baab2159a4f2%2Fa63075ad-e6f0-4efd-b2dc-d886b8e51a5f%2Fvhakjmb_processed.png&w=3840&q=75)
Transcribed Image Text:**Chemical Reaction Summary:**
\[ \text{H}_2(g) + \text{Cl}_2(g) \rightarrow 2 \text{HCl}(g) \]
**Conversions Used:**
- 1 mol = MW in g (to 2 decimal places) = 22.414 L
**Problem Statement:**
Determine how many grams of HCl (with MW = 36.46 g HCl) will be produced from 42.5 L of Cl\(_2\) gas (MW = 70.90 g Cl\(_2\)). Express the answer as 'g HCl'.
**Calculation Steps:**
\[ 42.5 \, \text{L Cl}_2 \times \frac{1. \, \_\_\_\_}{2. \, \_\_\_\_} \times \frac{3. \, \_\_\_\_}{4. \, \_\_\_\_} \times \frac{5. \, \_\_\_\_}{6. \, \_\_\_\_} = 7. \, \_\_\_\_ \]
**Calculation Details:**
1. **Conversion Factor 1: \_\_\_**
2. **Conversion Factor 2: \_\_\_**
3. **Conversion Factor 3: \_\_\_**
4. **Conversion Factor 4: \_\_\_**
5. **Conversion Factor 5: \_\_\_**
**Solution Space for Calculations:**
- Box 1: \_\_\_
- Box 2: \_\_\_
- Box 3: \_\_\_
- Box 4: \_\_\_
- Box 5: \_\_\_
Fill in each step with appropriate conversion factors and calculations to solve the problem.
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