+ Cl2(g) ----> 2 HClg) (OR H2(g) + Cl2(g) right arrow 2 HCIe) Use the following conversions: 1 mol = MW in g (2 d.p.) = 22.414 L What is the percent yield of HCl if 100.0 g of Cl2 (MW = 70.90 C12) creates 31.0 g of HCI (MW = 36.46 g HCI)? (Express with unit and compound, for example 'g Theoretical yield = Zn'). Percent yield = (Express as '%').
+ Cl2(g) ----> 2 HClg) (OR H2(g) + Cl2(g) right arrow 2 HCIe) Use the following conversions: 1 mol = MW in g (2 d.p.) = 22.414 L What is the percent yield of HCl if 100.0 g of Cl2 (MW = 70.90 C12) creates 31.0 g of HCI (MW = 36.46 g HCI)? (Express with unit and compound, for example 'g Theoretical yield = Zn'). Percent yield = (Express as '%').
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Chemical Reaction and Yield Calculation**
**Reaction Equation:**
H₂(g) + Cl₂(g) → 2 HCl(g)
(Alternatively written as: H₂(g) + Cl₂(g) → 2 HCl(g))
**Conversions to Use:**
1 mol = Molecular Weight (MW) in grams (rounded to two decimal places) = 22.414 L
**Problem Statement:**
What is the percent yield of HCl if 100.0 g of Cl₂ (with a molecular weight of 70.90) creates 31.0 g of HCl (with a molecular weight of 36.46)?
- **Theoretical Yield**: ________ (Express with unit and compound, for example 'g Zn').
- **Percent Yield**: ________ (Express as '%').
**Input fields for calculation:**
- Field to enter the theoretical yield labeled "Theoretical Yield."
- Field to enter the percent yield labeled "Percent Yield."
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