H20 (g) → H (g) + OH (g) Reaction 1: 2 H2 (g) + ½ O2 (g) → OH (g) AH1 = 38.95 kJ Reaction 2: H2 (g) + ½ O2 (g) → H20 (g) AH2 = – 241.8 kJ Reaction 3: H2 (g) → 2 H (g) AH3 = 496.0 kJ Reaction 4: O2 (g) → 20 (g) AH4 = 498.3 kJ

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The molecule, OH (g), is a free radical known as the "detergent" molecule of the atmosphere. The molecule, OH (g), is a free radical known as the "detergent" molecule of the atmosphere. La molécule, OH (g), est un radical libre connu sous le nom de molécule « détergente » de l'atmosphère. The molecule, OH (g), is a free radical called the “detergent” molecule of the atmosphere. La molécule OH (g) est un radical libre appelé molécule « détergente » de l'atmosphère. It reacts with many hydrocarbons or other molecules that enter the atmosphere to oxidize them into forms that can be removed from the atmosphere. It is present in very low concentrations at all times in the atmosphere, so the thermodynamics of its production is difficult to measure directly. To. Considering the enthalpy of the following reactions, determine the ΔH of the reaction: b) In which of the reactions listed (1 - 4) would ΔH be an enthalpy of formation, ΔfH °, and in which ΔH would be defined as ΔHdissociation (also known as binding energy)
Н2О (g) — Н (g) + ОН (9)
Reaction 1: 1 H2 (g) + 1 О2 (g) — ОН (g)
AH1 = 38.95 kJ
Reaction 2: H2 (g) + ½ O2 (g)
H20 (g)
AH2 = – 241.8 kJ
Reaction 3: H2 (g) → 2 H (g)
AH3 = 496.0 kJ
Reaction 4: O2 (g) → 2 O (g)
AH4 = 498.3 kJ
Transcribed Image Text:Н2О (g) — Н (g) + ОН (9) Reaction 1: 1 H2 (g) + 1 О2 (g) — ОН (g) AH1 = 38.95 kJ Reaction 2: H2 (g) + ½ O2 (g) H20 (g) AH2 = – 241.8 kJ Reaction 3: H2 (g) → 2 H (g) AH3 = 496.0 kJ Reaction 4: O2 (g) → 2 O (g) AH4 = 498.3 kJ
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