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H2 (g) + Br2 (g)=2 HBr (g) K = 20.13 An empty 6.87 L container at 201 K is filled with the gases listed below to the indicated initial concentrations. Based on the above reaction, calculate the equilibrium concentration of HBr. Initial Substance Concentration (M) H2 0.850 Br2 0.850 HBr 2.44

H2 (g) + Br2 (g)=2 HBr (g) K = 20.13 An empty 6.87 L container at 201 K is filled with the gases listed below to the indicated initial concentrations. Based on the above reaction, calculate the equilibrium concentration of HBr. Initial Substance Concentration (M) H2 0.850 Br2 0.850 HBr 2.44

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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H2 (g) + Br2 (g)=2 HBr (g) K = 20.13 An empty 6.87 L container at 201 K is filled with the gases listed below to the indicated initial concentrations. Based on the above reaction, calculate the equilibrium concentration of HBr. Initial Substance Concentration (M) H2 0.850 Br2 0.850 HBr 2.44
Transcribed Image Text:H2 (g) + Br2 (g)=2 HBr (g) K = 20.13 An empty 6.87 L container at 201 K is filled with the gases listed below to the indicated initial concentrations. Based on the above reaction, calculate the equilibrium concentration of HBr. Initial Substance Concentration (M) H2 0.850 Br2 0.850 HBr 2.44
Expert Solution
Step 1

Equilibrium constant is the ratio of product of concentration of products to the product of concentration of reactants raised to the power of their stoichiometric coefficient.

Given reaction : 

H2 (g) + Br2 (g) <=> 2 HBr (g)

For which the equilibrium constant (K) is 20.13.

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