H.W5: A cast-iron channel supported at two points, 11 m apart, carries water as shown in figure below. Determine the maximum depth of water in the channel if the tensile and compressive bending stresses are not to exceed 18 MPa and 48 MPa respectively. Water weighs 9.81 kN/m³ and the cast iron 68 kN/m³. Ans. Max. Depth = 203 mm

Q: A 8.4 kN 4.5 m B C 8.4 kN 4.5 m 28 m

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Q: Compute the value of EIy at 2.5 m from the left support.

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Q: Determine the maximum shear stress developed in the 44 mm diameter shaft.

A: Introduction- A component with a circular cross-section that spins and conveys power from a driving…

Q: A B C D 40 kN.m 60 kN•m E OK 30 kN-m 50 kN-m

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Q: The structure supports a distributed load of "w". The limiting stress in rod (1) is 380 MPa, and the…

A: We will find allowable load in rod and pin and take minimum of that value. We will take moment at C…

Q: Determine the maximum total stress in the cross section for the below beam. 50 kN 3 60 kN D B 2 m 2…

A: Calculate support reaction at support A and D:

Q: a. Draw free body diagram b. Determine support reactions c. Determine stress in the cables d.…

A: In the problem, first the FBD diagram has to be drawn following which the support reactions will be…

Q: (1) 1.6 m B P 2.8 m (2) C

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Q: The most concrete object on the Ladder of Abstraction is a photograph or painting, i.e., the object…

A: True the most concrete object on the Ladder of Abstraction is a photograph or painting, i.e., the…

Q: Determine the Reactions of each beam. Show the Distributed Load Resultant magnitude and location on…

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Q: 2. The member is to be made from a steel plate that is 5cm thick. If a 1cm. hole is drilled through…

A: Allowable stress= 150 MPa  Thickness of plate= 5 cm  Diameter of hole= 1 cm

Q: Q3. Determine the force in members CE, DE, and DF.

A: α=tan-12-0.42.4×4=9.4623DC=0.4+2-0.49.6×2.4=0.8β=tan-10.82.4=18.434   Support reaction:…

Q: 3. The 500-kg uniform beam is subjected to the three external loads shown. Compute the reactions at…

A: The beam weight = 500 kgThe reactions at the support point O =?

Q: A steel penstock has a 36-in. outer diameter, a 0.5-in. wall thickness, and connects a reservoir at…

A: Given:Outer diameter= 36 inchthickness= 0.5 inchh = 600 ftRequired:Maximum normal and shear stress

Q: For the portal frame shown in the given figure, the shear equation is B 4 m (a) (b) (c) (d) P MBC +…

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Q: For the beam and loading condition, consider section n-n and determine (a) The largest stress in the…

A: Given data:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.