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H. Calculate AGRxn using the AG values in your references. I. Is the reaction spontaneous at this temp? Give your reasoning. J. Is the reaction spontaneous at all temps? If not, calculate the temperature at which it switches to being non-spontaneous.

H. Calculate AGRxn using the AG values in your references. I. Is the reaction spontaneous at this temp? Give your reasoning. J. Is the reaction spontaneous at all temps? If not, calculate the temperature at which it switches to being non-spontaneous.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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25, I need part G, H, I, J please!
H. Calculate AGORxn using the AGº values in your references. I. Is the reaction spontaneous at this temp? Give your reasoning. J. Is the reaction spontaneous at all temps? If not, calculate the temperature at which it switches to being non-spontaneous.
Transcribed Image Text:H. Calculate AGORxn using the AGº values in your references. I. Is the reaction spontaneous at this temp? Give your reasoning. J. Is the reaction spontaneous at all temps? If not, calculate the temperature at which it switches to being non-spontaneous.
25. CS2(g) + 4H2(g) → CH4(g) + 2 H₂S(g) at 298 K and 1 atm A. Calculate AHORxn for the above reaction, using the AH values in your references. 4 H "ren = [(mm) X(-241031 km) +2max ( - 20.63 (05/ml)] - (Imax (115.3 leJ/mol ) to] 41126 ks] [115,3 (5] Han = [-74.81 kes AH yan Asran -23 137 B. Is this reaction exothermic or endothermic? C. Will it favor spontaneity based on enthalpy? yes D. What would you predict the sign of ASORxn to be. Give your reasoning. 145 moles) m right circle = 1+2=3 moles Xo thermie 9 G. Calculate AGORxn using the Gibbs Free Energy equation. this means entropy has deacreased! So Sign of Agen E. Calculate the ASORxn using the Sº values in your references. 205.6, C52 237.91 #2 139.7 CHA: 182126, 1125 = [toolx (182.26 5//imol ) + 2max X (203.68/kmal) ]-[Imax (237.95/1) + Amolx (13017 /mol)] => AS F. Did your result match your prediction? Would be hejative! A5593.46-760.7 As = [-167.240/12 rin PgUp 9 6 IS
Transcribed Image Text:25. CS2(g) + 4H2(g) → CH4(g) + 2 H₂S(g) at 298 K and 1 atm A. Calculate AHORxn for the above reaction, using the AH values in your references. 4 H "ren = [(mm) X(-241031 km) +2max ( - 20.63 (05/ml)] - (Imax (115.3 leJ/mol ) to] 41126 ks] [115,3 (5] Han = [-74.81 kes AH yan Asran -23 137 B. Is this reaction exothermic or endothermic? C. Will it favor spontaneity based on enthalpy? yes D. What would you predict the sign of ASORxn to be. Give your reasoning. 145 moles) m right circle = 1+2=3 moles Xo thermie 9 G. Calculate AGORxn using the Gibbs Free Energy equation. this means entropy has deacreased! So Sign of Agen E. Calculate the ASORxn using the Sº values in your references. 205.6, C52 237.91 #2 139.7 CHA: 182126, 1125 = [toolx (182.26 5//imol ) + 2max X (203.68/kmal) ]-[Imax (237.95/1) + Amolx (13017 /mol)] => AS F. Did your result match your prediction? Would be hejative! A5593.46-760.7 As = [-167.240/12 rin PgUp 9 6 IS
Expert Solution
Step 1

G , H ) We can calculate the following values using the formula. 

I ) The reaction is said to be spontaneous if value of ∆G°rxn is negative. 

J) we can calculate the temperature using the condition for non-spontaneous reaction. 

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