SOLVE STEP BY STEP IN DIGITAL FORMATMALESClearClearYellowishClearYellowishYellowishwith ringswith ringsFEMALESClearYellowisha. hypothesisb. ClearClearwith ringsYellowishc. Yellowishd. With ringswith ringsYellowishwith ringsCLEAR927814075000YELLOWISH07012208141122340WITH RINGS0000681281. Several crosses between pheasants that differed in plumage color gave the followingresults:38347What hypothesis, regarding the type of dominance, would you propose that bestexplains the results? Use the letter p as a basic symbol to designate the differentalleles. Based on this symbol, determine the genotypes that correspond to the light,yellowish, and ringed phenotypes.

On the basis of data provided above, clear phenotype is observed in all crosses when at least one…

Answered: h S Clear with rings Yellowish with…

Similar questions

In jabuticaba tree plant, Plinia cauliflora, the AA, Aa plants round fruit and aa oval fruit, the CC, Cc individuals show dark purple fruit and cc individuals are yellow; for the B locus B1B1 plants have all the fruit in their bark, B2B2 plants have fruit in the branches only and B1B2 plants have fruit in their bark and branches. A trihybrid jabuticaba having the genotype AaB1B2Cc is self-fertilized. Is there complete dominance at the B loci, yes or no? Please explain.
Answer pls
Consider the following three point trihybrid testcross ibvolving traits in dragons. The genotypes determining the 8 progeny types from this testxross are shown below out of a sample of 1572 flies. What number of progeny for each genotype would you predict in the case of independent assortment. gametes number K L M 621 klm 608 k L M 103 K lm 109 K lm 64 k L m 57 K L m 3 k l M 7
Using the numbers of observed F2 progeny provided in the table (attached picture), write a proper hypothesis of your expectations for the phenotypic ratios in the F2 generation and use this to complete the rest of the table.
Two different house Flys were crossbreed for 2 generations. The female was a wild fly and the male was a mutant with apterous wings and a black body. Given the data of the second generation: is this data consistent with the expected 9:3:3:1 ratio expected of a dihybrid cross?
21 smooth/yellow 42 smooth/light-yellow 19 smooth/white 22 wrinkled/yellow 39 wrinkled/light-yellow 20 wrinkled/white What is the most likely parental cross used to obtain the ratios of phenotypes we see here? Why?
please answer all parts
A researcher crosses two tall plants, however, one quarter (1/4) of the offspring from this crossing have short stems. Complete the punnett square. 6 b EBE Bb Besides Bb, what is the other possible genotype for a tall plant? What is the genotype of a short plant? Bb bb
In goats, black fur is dominant to red fur. The gene for this trait can be described as Bb (if you forgot why this is so, go back and reread the background information at the beginning of this exercise). A homozygous black female goat (nanny) is crossed with a heterozygous male (billy). 3 Using this information, fill in Punnett square A to predict the potential genotypes of offspring that could result from this cross. Fill input: Fill input: Fill input: Fill input: Fill input: Fill input Fill input: Fill input: Punnet Square A BB B Bb BB Bb B B
In'a Mendelian monohybrid cross, the F2 generation consists of 1/4 red-flowered, 1/2 pink-flowered, 1/4 white-flowered individuals. What does this indicate? For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). 14px A Ix BIUS Paragraph Arial ABC 田三 x² X2 田用因 Ť {} +]
Spotted lanternfly females were crosses with males possessing short wings (sw) ebony body (e) and sephia (s) eyes, which are recessive traits. 1000 offspring were counted, and the results are shown in the table. below. No determination of sex was made. Using proper notation determine the linkage-genotype of the female parent. Determine the sequence of the three genes and map the distances between them. Calculate the COC and interference in the cross and describe what it means. Phenotype ++ e S SW + s + + + sw e + + + S SW e se + sw + #offspring 332 331 111 121 46 56 7 6