Consider two different traits in mice affecting tail length and fur color. A two-factor cross wasmade involving true-breeding mice with short tails and white fur to wild-type mice withtails and brow | fur, All FL offspring had long tails and brown fur. The F1 offspring were thentotal to mice with short tails and white fur. The following phenotypic results were obtained.118 long fails, brown fu77 long tails, white fur114 short tails, white fur81 short tails, brown furConstruct a null hypothesis about these two genes and the expected ratios of theoffspring from the cross.

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Answered: Consider two different traits in mice…

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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We are interested in detremining the genetic map of three different house finch traits: beak color (dark vs light), song length (short vs long) and patch size (reduced vs normal). We have done a large experiment involving the usual PO crossed, with the F1 test crossed. The following are the data for the offspring from the test cross: Beak Shade Patch Size Song Length Number Observed Dark Normal Long 67 Light Normal Long 3 Light Normal Short 498 Dark Normal Short 43 Dark Reduced Short 13 Light Reduced Short 80 Light Reduced Long 50 Dark Reduced Long 389 Choose the map below that best fits the data Beak Shade- 14.26CM- Patch Size- 9.54CM-Song Length O Patch Size-9.54cM- Beak Shade- 14.26CM-Song Length O Patch Size- 14.26cM- Beak Shade- 9.54CM-Song Length O Beak Shade-9.54cM-Patch Size- 14.26CM-Song Length O Patch Size-9.54CM- Song Length- 14.26CM-Beak Shade O Patch Size- 14.26cM-Song Length- 9.54cM-Beak Shade
Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Part A: Record the phenotypes and the phenotype ratio in lowest terms. Part B: Convert the expected phenotypic ratio from Part A into the expected probability for each of the four phenotypes and record them in the table below. Calculate the probability for each of the four phenotypes observed in the cross from the data presented at the beginning of the question by dividing the number of progeny in each class by the total number of progeny and record these in the table below. (Probability = Number of Progeny in Phenotype…
In the rat, the pattern of coat color is affected by a gene with two alleles. PH is the allele for hooded, in which the animal is mostly white with color restricted to the shoulders and neck. P+ is the normal solid body color allele. These two alleles exhibit incomplete dominance, so that heterozygotes have white bellies only. A true-breeding solid strain is crossed with a true-breeding hooded strain, to produce an F₁ generation that is all white belly. The F₁ generation rats are mated with each other to produce 800 F₂ offspring. Below is a table that gives the observed number of each phenotype in the F2 and also gives you the expected number. Question: If you perform a Chi-square goodness of fit test, what is the value of Chi square X² (Express your answer to the hundredths.) solid white belly hooded Σ Observed 195 420 185 800 Expected 200 400 200 800
The following results were obtained from a dihybrid cross between two pea plants: 315 plants with round seeds and yellow flowers 101 plants with wrinkled seeds and yellow flowers 108 plants with round seeds and white flowers 32 plants with wrinkled seeds and white flowers Assume that round seeds and yellow flowers are dominant and both parent plants were heterozygous for both traits.
The data set attached summarizes F2 numbers from an F1 cross arising from two, true-breeding Drosophila strains (P generation), which differ with respect to two mutant traits. Here are the hypothesis: Leg length - The wild-type and mutant alleles for leg length are incomplete dominant relative to each other. Justification: The data set includes three phenotypic categories for leg length: wild type (long leg), medium leg, and truncated wings. The presence of three distinct phenotypes suggests an incomplete dominance pattern, where the heterozygous individuals exhibit an intermediate leg length phenotype (medium leg). The absence of purebred short-legged individuals supports the idea that the long leg allele is dominant over the short leg allele. This shows that mode of inheritance is incomplete dominance of the alleles relative to each other. Since the data does not mention any specific differences between males and females, we can assume that the mode of inheritance for the trait is…
Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Complete a Punnett square to determine the expected testcross progeny on the basis of Mendel’s Law of Independent Assortment. Record the phenotypes and the phenotype ratio in lowest terms.
A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous wild type male. The resulting progeny were allowed to mate with one another to produce the data set. Three repetitions of the experiment were conducted. The following data were produced from the crosses. Test these data to determine if they are significantly different from the expected phenotypic ratio. Use the 5% level of significance. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject for each experiment. Wild eye Wild body – 112, Wild eye Ebony body – 40, Sepia eye Wild body – 35, Sepia eye Ebony body – 11
In garden pea, resistance to a certain disease is controlled by a single locus with dominance forresistance (R) and recessive susceptible (r). Another locus governs seed color with yellow being dominant (Y)to green (y). A pea plant which is heterozygous for both gene pairs is crossed with a susceptible and green-seeded plant. The following data was observed in the progeny. Phenotype NumberResistant yellow 43Susceptible green 49Resistant green 16Susceptible yellow 12Total 120 a. What is the calculated chi-square value based on an independent assortment assumption? Compute forthe df and write the conclusion. (NOTE: The cross will not yield a 9:3:3:1 ratio since not both of theparental genotypes are heterozygous for the 2 pairs of alleles. Thus, perform the cross first, show theparental genotypes, the gamete…

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