h Initial Kr A 4.7 kg ball is at the top of a 2.1 meter ramp. What is the potential energy of this system? U = 96.72 ✓ The ball has a moment of inertia of 1 = 0.17 kg*m². By the time it reaches the bottom, it is spinning at 7 rad/s. What is its rotational ketic energy? = 4.16 O. unit J Final X unit m/s Assuming no energy loss to friction, what should the linear speed of the ball be? V = 1.33

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h
Initial
A 4.7 kg ball is at the top of a 2.1 meter ramp. What is
the potential energy of this system?
U = 96.72
Kr
प्र
= 4.16
unit J
The ball has a moment of inertia of 1 = 0.17 kg*m². By
the time it reaches the bottom, it is spinning at 7 rad/s.
What is its rotational kaetic energy?
O.
Final
unit J
Assuming no energy loss to friction, what should the
linear speed of the ball be?
V = 1.33
X unit m/s
Transcribed Image Text:h Initial A 4.7 kg ball is at the top of a 2.1 meter ramp. What is the potential energy of this system? U = 96.72 Kr प्र = 4.16 unit J The ball has a moment of inertia of 1 = 0.17 kg*m². By the time it reaches the bottom, it is spinning at 7 rad/s. What is its rotational kaetic energy? O. Final unit J Assuming no energy loss to friction, what should the linear speed of the ball be? V = 1.33 X unit m/s
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