H₂ + I₂ ZHI kc = 73.5 when 6.4 mole He and 3.6 moles Iz are placed in zu Flask what [HI] will be produced at Equilibrio O H₂+I₂ = 2HI Ke= [HI]² [Hz] [1₂] ¹ 3.2 1.8 H₂ + I₂ = 2HT X 3.2 1.8-X 2 2 CHIT [4₂] [1₂] Kc =
H₂ + I₂ ZHI kc = 73.5 when 6.4 mole He and 3.6 moles Iz are placed in zu Flask what [HI] will be produced at Equilibrio O H₂+I₂ = 2HI Ke= [HI]² [Hz] [1₂] ¹ 3.2 1.8 H₂ + I₂ = 2HT X 3.2 1.8-X 2 2 CHIT [4₂] [1₂] Kc =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I'm stuck on how to solve the equation.
![H₂ +I₂ 2HI
t E
kc = 73.5
when 6.4 mole He and 3.6 moles Iz
어
are
placed in
what [HI] will be produced at Equilibrio
3.2 1.8
6 H₂ + I₂ = ZHT
3.2-2 1-8-X
X
[HI]²
2L Flask what [HI]
H₂+I₂ = 2HI
Ke= [HI]²
3.2-X 1.4-x
[Hz] [Iz]!
3-2
1.8
6
H₂ +1₂==== ZHI
2X
Kc =
[1/₂] [1₂]'](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffd4c8a78-94ed-40f4-97b5-ac0eacd4f1aa%2F3aaa2340-642b-4009-afaa-8f441709c3dd%2F9k27hr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:H₂ +I₂ 2HI
t E
kc = 73.5
when 6.4 mole He and 3.6 moles Iz
어
are
placed in
what [HI] will be produced at Equilibrio
3.2 1.8
6 H₂ + I₂ = ZHT
3.2-2 1-8-X
X
[HI]²
2L Flask what [HI]
H₂+I₂ = 2HI
Ke= [HI]²
3.2-X 1.4-x
[Hz] [Iz]!
3-2
1.8
6
H₂ +1₂==== ZHI
2X
Kc =
[1/₂] [1₂]'
Expert Solution
Step 1
According to the question,
The balanced equation for the reaction is:
The equilibrium constant for the reaction is given as Kc = 73.5
The initial amounts of H2 and I2 are given as,
Find- The concentration of HI at equilibrium
Step by step
Solved in 4 steps
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