Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Provide the mechanism of the reaction shown below.

Transcribed Image Text:This image depicts a chemical reaction involving the formation of a thiochromene compound.
**Reactants:**
1. **Sodium Thioacetate (left):** Represented by its chemical structure with a negative charge on the sulfur (S^-).
2. **Chalcone (center):** Shows a phenyl group (benzene ring) connected via a double bond to a carbonyl group (C=O) and an aldehyde group (H-C=O).
**Catalyst:**
- **Triethylamine (HN(Et)_3/NEt_3):** This acts as a base, facilitating the reaction.
**Product:**
- **Thiochromene derivative (right):** The resulting compound includes a fused ring system with both benzene and thiopyran rings. It includes a sulfur atom and retains a formyl group (C=O) attached to the ring system.
**Reaction Overview:**
The reaction involves the use of a base, shown as triethylamine, to catalyze the cyclization of sodium thioacetate and chalcone, resulting in the formation of a thiochromene derivative. This transformation includes the creation of a new carbon-sulfur bond and the formation of a heterocyclic compound.
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