H-Br CH₂OOCH3 :Br:

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Chapter1: Chemical Foundations
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Give a curved arrow-pushing mechanism for the following reaction and make sure to include all the nonbonding electrons, clearly indicate  the initiation and propagation steps.

This image depicts a chemical reaction of an alkene undergoing a hydrohalogenation process.

**Reaction Description:**

- **Starting Material (Left Side):** 
  - The structure is an alkene with the chemical formula representing an isobutylene (2-methylpropene). This molecule has a double bond between two carbon atoms.

- **Reagent (Above the Arrow):**
  - Hydrogen bromide (H-Br) is used as the reagent, and dimethyl ether (CH\(_3\)OCH\(_3\)) is present as a solvent or a reaction medium.

- **Product (Right Side):**
  - The product is an alkyl halide where the double bond is replaced with a bromine atom attached to the more substituted carbon due to Markovnikov's rule, resulting in 2-bromo-2-methylbutane. The bromine is shown with lone pairs of electrons.

This reaction illustrates the addition of a hydrogen halide (H-Br) to an alkene, resulting in the formation of a haloalkane, where the bromine atom adds to the carbon atom bearing more alkyl groups. This follows the Markovnikov's rule, which states that in the addition of HX to alkenes, the hydrogen atom attaches to the carbon with more hydrogen atoms, and the halogen attaches to the carbon with more alkyl groups.
Transcribed Image Text:This image depicts a chemical reaction of an alkene undergoing a hydrohalogenation process. **Reaction Description:** - **Starting Material (Left Side):** - The structure is an alkene with the chemical formula representing an isobutylene (2-methylpropene). This molecule has a double bond between two carbon atoms. - **Reagent (Above the Arrow):** - Hydrogen bromide (H-Br) is used as the reagent, and dimethyl ether (CH\(_3\)OCH\(_3\)) is present as a solvent or a reaction medium. - **Product (Right Side):** - The product is an alkyl halide where the double bond is replaced with a bromine atom attached to the more substituted carbon due to Markovnikov's rule, resulting in 2-bromo-2-methylbutane. The bromine is shown with lone pairs of electrons. This reaction illustrates the addition of a hydrogen halide (H-Br) to an alkene, resulting in the formation of a haloalkane, where the bromine atom adds to the carbon atom bearing more alkyl groups. This follows the Markovnikov's rule, which states that in the addition of HX to alkenes, the hydrogen atom attaches to the carbon with more hydrogen atoms, and the halogen attaches to the carbon with more alkyl groups.
Expert Solution
Step 1: Free radical reaction

Free radicals are neutral, reactive species.

Free radicals are formed by homolytic cleavage.

The carbon free radical is a species which contains 7 valence electrons.

Stability order of carbon free radical :- methyl radical< primary radical<secondary radical< Tertiary radical.


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