group of 200 university students is randomly selected to participate in an IT survey campaign. From the survey, 70 of them responded “Yes” when they were asked whether they used a tablet to take notes in the i) Construct a 95% confidence interval for the true ii) How would the confidence interval change if the confidence level is 90%? iii) What sample size is needed if the margin of error in part (a)(iii) is decreased by half?

Q: Nina would like to estimate the difference in the mean amount of time students spend on math…

A: Total number of sample =30 90% confidence interval for the true difference in the population means,…

Q: The university decided to conduct a satisfaction survey to assess the proportion of students likely…

A:

Q: A poll of 827 students at Alpha State College found that 61% of those polled preferred a quarter…

A: Given that Sample size n = 827 Sample proportion of students who prefer a quarter system = 0.61 The…

Q: If you need to make a 98% confidence interval for a proportion, and the margin of error is to be no…

A: Given information:  Confidence level = 98% Margin of error (e) = 0.025 Let proportion (p) = 0.5 The…

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 445 green…

A: a. Construct a 90​% confidence interval to estimate of the percentage of yellow peas.b. It was…

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 439 green peas…

A:

Q: The National Health and Nutrition Examination Survey is conducted each year and contains a variety…

A: There are two independent samples which are year 2003 and year 2018. Both samples come from…

Q: n a study of speed​ dating, male subjects were asked to rate the attractiveness of their female​…

A: Solution: x (x-x) (x-x)2 6 -0.75 0.5625 8 1.25 1.5625 2 -4.75 22.5625 10 3.25 10.5625…

Q: A U.S. Travel Data Center survey of 500 adults found that 195 said they would take more vacations…

A: Given: n= 500 ,x= 195.0 At 95.0 % confidence level , z score= 1.96 Need to find confidence interval…

Q: In a study of speed dating, male subjects were asked to rate the attractiveness of their female…

A:

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 449 green peas…

A: Given that - A genetic experiment with peas resulted in one sample of offspring that consisted of…

Q: A survey of 180 students is selected randomly on a large university campus. They are asked if they…

A: 95% confidence interval is (0.328, 0.472)Sample Size, Number of successes,

Q: in a survey of 2043 adults in a recent year, 741 made a New Year's resolution to eat healthier.…

A:

Q: Among the 34,506 people who​ responded, 63​% answered​ "yes."   Use the sample data to construct a…

A: Given data: Total number of people who responded for the question presented by online site, n =…

Q: A survey of 200 students is selected randomly on a large university campus. They are asked if they…

A: given data 98% CI for P :(0.603,0.757) n=200 x=136 p^=xn=136200=0.68find 95% CI

Q: How large would the sample need to be so that a 95% confidence interval would have a margin of…

A:

Q: random samples of 11,559 California and 4,685 Oregon residents. Calculate a 95% confidence interval…

A: See the hand writing solution

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 437 green peas…

A:

Q: A clinical trial tests a method designed to increase the probability of conceiving a girl. In the…

A: From the provided information, n = 580 and x = 319 The proportion can be obtained as:

Q: periment with peas resulted in one sample of offspring that consisted of 419 green peas and 159…

A: a. The value of z at 95% confidence level is 1.96 (from z table). The sample proportion is computed…

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: ccording to a past poll conducted of Lexington residents, 52% indicated support for a light rail…

A: Given: Sample proportion p^=52%=0.52 Sample size (n) = 400

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 431 green peas…

A:

Q: A genetic experiment with peas resulted in one sample of offspring that consisted of 424 green peas…

A: The question is based on a confidence int. of a popl. prop. Given : Total no. of green peas ( y )=…

Q: (b) If the sample size were n = 36, would the confidence interval still be valid? (Choose one)

A: We are asked to check whether the confidence interval is valid for the sample size of 36 or not.…

Q: In a study of speed​ dating, male subjects were asked to rate the attractiveness of their female​…

A: For given sample, x¯=6.6667, from the excel function, =AVERAGE(G17:G28)s=2.2697  from the excel…

Q: In a study of speed dating, male subjects were asked to rate the attractiveness of their female…

A: We have given data is as follow: 6 9 3 8 4 6 7 7 9 9 5 9 The confidence interval CL=0.95

Q: A study of 420,034 cell phone users found that 138 of them developed cancer of the brain or nervous…

A: Solution: It is given that, out of 420034 cell phone users 138 developed cancer of the brain or…

Q: Part 1 of 3: In a survey of 345 randomly selected gun owners, it was found that 52 of them said they…

A: It is given that a survey of 345 randomly selected gun owners, it was found that 52 of them said…

Q: A Pesearcher asks à random sample of 200 Virginia residents whether they take a multivitamin on a…

A: Assume that p is the true population proportion of Virginal residents, who take a multivitamin.

Q: et: Confidence Intervals for Proportions 1. The paralyzed Veterans of America is a philanthropic…

A: Given : n=100000 x=4781 c=95%=0.95

Q: In a random sample of 200 people, 74% of them said that they do go to Truecar.com before they go…

A: It is given that 74% out of 200 people said that they do go to Truecar.com before they go shopping…

Q: 1) In a survey on supernatural experiences, 712 of 4019 adult Americans surveyed reported that they…

A: Let X be total number number of supernatural experiences.And N is the total number of adults in…

Q: The 95% confidence interval is ....<(p1-p2)<.

A: The 95% confidence interval is ....&lt;(p1-p2)&lt;....…

Q: a) We would next like to construct a 95% confidence interval for the difference ?1−?2p1−p2. What is…

A: p1 denotes the proportion of homes with asbestos in Kingston and p2 denotes the proportion of homes…

Q: A journal article reports that a random sample of 25 antivirus software packages was used as a basis…

A: given data  98% confidence interval for μ :  (206,293) margin of error (E) = ?

Q: a) What proportion of workers answered yes to the survey? b) What was the margin of error?

A: Here, the 95% confidence interval for the proportion of workers that answered 'yes' is (0.62, 0.73).…

Q: A study of 420,007 cell phone users found that 136 of them developed cancer of the brain or…

A: Given, n = 420007 X = 136 p^ = Xn = 136420007 = 0.000324 Confidence level = 0.90     To find, a. 90%…

Q: The test statistic, t, is (Round to two decimal places as needed.) The P-value is (Round to three…

A:

Q: a. Construct a 90​% confidence interval to estimate of the percentage of yellow peas. b. It was…

A: Let x1 be the number of yellow peas=164 x2 be the number of green peas=441

Q: genetic experiment with peas resulted in one sample of offspring that consisted of 412 green peas…

A: Given that  Sample size n = 412 + 151 n=563 Favorable cases x =151 Sample proportion p^=x/n…

Q: A random sample of five orders was selected from a year of trading, carried out by a kitchen…

A: Solution-: Given data: 51,45,73,48,55 We want to find,  (a) Construct a 95% confidence interval for…