1) In a survey on supernatural experiences, 712 of 4019 adult Americans surveyed reported that they had seen orbeen with a ghost. Assume that all the required assumptions were met for us to construct a confidence intervalto estimate the proportion of all adult Americans who have seen or been seen with a ghost.(a) (4) Construct a 90% confidence interval for the proportion of all adult Americans who have seen or been with aghost. (Round answers to 3 dec.) put answer into interval below. Show the formula and fill in the pieces to getyour interval.Answer: ()Calculate p to 4 decimal places to put into the formulaFormula and solution:p =Formula for confidence interval: Fill in the values. Give the interval.enodig llao e no gabilst slide trigil ben oulev bne side egongb) (3) Give an Interpretation of your interval.aniwA Lebc) (2) Would a 99% confidence interval be narrower or wider than the interval computed in part (a)?

Let X be total number number of supernatural experiences.And N is the total number of adults in…

Answered: 1) In a survey on supernatural…

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.3: Measures Of Spread

Problem 1GP

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8.2 question 5). In 2013, the Gallup poll asked 1,039 American adults if they believe there was a conspiracy in the assassination of President Kennedy and found that 634 believe there was a conspiracy ("Gallup news service," 2013). Estimate the proportion of American’s who believe in this conspiracy using a 98% confidence interval.
Suppose that a health expert has claimed that 28% of college students smoke cigarettes. To investigate this claim, researchers survey a random sample of college students. Using this sample, a 95% confidence interval for the percentage of college students who smoke is found to be 19% to 24%. On the basis of this interval, explain whether the claim that 28% of all college students smoke is reasonable or not. You may need to use the appropriate table in the Appendix of Tables to answer this question. a) The claim of 28% is reasonable because the value 28% is not in the confidence interval. b) The claim of 28% is not reasonable because the value 28% is in the confidence interval. c) The claim of 28% is not reasonable because the value 28% is not in the confidence interval. d) The claim of 28% is reasonable because the value 28% is in the confidence interval.
In a survey on supernatural experiences, 722 of 4019 adult Americans surveyed reported that they had seen or been with a ghost. (a) What assumption must be made in order for it to be appropriate to use the formula of this section to construct a confidence interval to estimate the proportion of all adult Americans who have seen or been with a ghost? O we need to assume that the 722 people are the only Americans who had seen or been with a ghost. O we need to assume that the 4019 people formed a random sample of adult Americans. O Wwe need to assume that there are only 722 adult Americans. O we need to assume that the 4019 people were surveyed at a supernatural convention. (b) Construct a 90% confidence interval for the proportion of all adult Americans who have seen or been with a ghost. (Round your answers to three decimal places.) Interpret the interval. O We are confident that the proportion of all adult Americans who have seen or been with a ghost is within this interval 90% of the…
The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and universities. Suppose we take a poll (random sample) of 3878 students classified as Juniors and find that 3241 of them believe that they will find a job immediately after graduation. Find the 95% confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. Use Z = 1.96. Use the unrounded values in Excel to find the answers to #2, #3 and #4. 1. Find the sample proportion of GSU Juniors who believe that they will, immediately, be graduation. 2. The standard error for sample proportion has a value of 3. The margin of error has a value of --
A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 27 patients were recorded before administering the drug and after. The 99% confidence interval for the true mean difference in total cholesterol levels (after - before) was (-78.82, -31.18). Which of the following is the appropriate conclusion? Question 4 options: 1) We are 99% confident that the average difference in cholesterol levels is positive, with the higher cholesterol levels being before the drug regimen. 2) We are 99% confident that the average difference in cholesterol levels is positive, with the higher cholesterol levels being after the drug regimen. 3) We are 99% confident that the average difference in cholesterol levels is negative, with the higher cholesterol levels being before the drug regimen. 4) We are 99% confident that the average difference in…
If the number of smokers in a sample of 40 students selected from university A is 14 and the number of smokers in a sample of 380 students selected from university B is 84. Then the 99% confidence interval for the difference between proportions of smokers in the two universities (PB- PA) is closest to O a. (-0.1450,-0.1130) O b. (-0.3310,0.0729) O c. None of these o d. (-0.3110,0.0534) e. (-0.1430,-0.1150)
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