> (bonus) We say that A B if A(X) = ✓ anX" and B(X) = bnX" and an ≤ bn for all n ≥ 0. n≥0 n≥0 Consider subsets of {1,2,,q}, where some subsets are "special". We are not told what "special" means exactly, except that the subsets of a special set are also special (other subsets might be special too). For each n, the number of special subsets is Sn, and S(X) = Σn20 SnXn. Show that if there exists a special subset of size p then (1+X) P ≤ S(X) ≤ (1+X)ª.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 16E
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(bonus) We say that A B if A(X) = ✓ anX" and B(X) = bnX" and an ≤ bn for all n ≥ 0.
n≥0
n≥0
Consider subsets of {1,2,,q}, where some subsets are "special". We are not told what "special" means
exactly, except that the subsets of a special set are also special (other subsets might be special too). For
each n, the number of special subsets is Sn, and S(X) = Σn20 SnXn.
Show that if there exists a special subset of size p then (1+X) P ≤ S(X) ≤ (1+X)ª.
Transcribed Image Text:> (bonus) We say that A B if A(X) = ✓ anX" and B(X) = bnX" and an ≤ bn for all n ≥ 0. n≥0 n≥0 Consider subsets of {1,2,,q}, where some subsets are "special". We are not told what "special" means exactly, except that the subsets of a special set are also special (other subsets might be special too). For each n, the number of special subsets is Sn, and S(X) = Σn20 SnXn. Show that if there exists a special subset of size p then (1+X) P ≤ S(X) ≤ (1+X)ª.
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