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> 2. Predict the products and draw the mechanism of the reaction below showing any relevant transition states. Additionally, name the reactant and the product properly indicating stereochemistry. ch₂ Br NaOEt DMSO CH

> 2. Predict the products and draw the mechanism of the reaction below showing any relevant transition states. Additionally, name the reactant and the product properly indicating stereochemistry. ch₂ Br NaOEt DMSO CH

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Step 2: Reaction Mechanism and Stereochemistry** **Reaction Task:** Predict the products and draw the mechanism of the reaction below, showing any relevant transition states. Additionally, name the reactant and the product properly indicating stereochemistry. **Reactant:** - A cyclohexane ring with a bromine (Br) atom attached at one position. The bromine is shown with a wedge, indicating it is coming out of the plane. Attached to the same carbon is a hydrogen, represented with a dash, indicating it is going into the plane. **Reagents:** - Sodium ethoxide (NaOEt) - Dimethyl sulfoxide (DMSO) **Product:** - Cyclohexene with a methyl group (CH₃) attached, represented with a wedge. **Explanation:** The reaction likely involves elimination, where the NaOEt acts as a base, removing the hydrogen atom that is anti to the bromine, leading to the formation of a double bond and the departure of the bromine atom as a leaving group. This results in the formation of cyclohexene with appropriate stereochemistry.
Transcribed Image Text:**Step 2: Reaction Mechanism and Stereochemistry** **Reaction Task:** Predict the products and draw the mechanism of the reaction below, showing any relevant transition states. Additionally, name the reactant and the product properly indicating stereochemistry. **Reactant:** - A cyclohexane ring with a bromine (Br) atom attached at one position. The bromine is shown with a wedge, indicating it is coming out of the plane. Attached to the same carbon is a hydrogen, represented with a dash, indicating it is going into the plane. **Reagents:** - Sodium ethoxide (NaOEt) - Dimethyl sulfoxide (DMSO) **Product:** - Cyclohexene with a methyl group (CH₃) attached, represented with a wedge. **Explanation:** The reaction likely involves elimination, where the NaOEt acts as a base, removing the hydrogen atom that is anti to the bromine, leading to the formation of a double bond and the departure of the bromine atom as a leaving group. This results in the formation of cyclohexene with appropriate stereochemistry.
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