Grades of g1 = -1.50% and 92 = +2.50%, VPIelevation 750.00 ft at station 30+ 00. Fixedelevation 753.00 ft at station 30 +00.Part AField conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations. Give the elevations in order of increasing X.Express your answers in feet to five significant figures separated by commas.Elev =SubmitV~ ΑΣΦ ↓↑Request AnswervecĆ?ft

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Answered: Grades of g1 = -1.50% and g2 = +2.50%,…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Grades of g₁ = -0.50% and g₂ = +3.50%, VPI elevation 750.00 ft at station 30+ 00. Fixed elevation 753.00 ft at station 30 +00. Part A Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations. Give the elevations in order of increasing X. Express your answers in feet to five significant figures separated by commas. Elev = 15| ΑΣΦ ↓↑ vec ? ft
Grades of g1 = -2.50% and g2 = +1.50%, VPI elevation 850.00 ft at station 22 + 00, and a fixed elevation 854.00 ft at station 20 + 50. Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations. Give the elevations in order of increasing X . Express your answers in feet to five significant figures separated by commas.
A-2.50% grade meets a +1.75% grade at station 44+25 and elevation 3385.74 ft, 400-ft curve, stakeout at half stations. Part A Determine the elevation at the low point of the curve Express your answer in feet to six significant figures. Elev= VAΣ1 vec + A ft
Grades of g₁ = -2.50% and 9₂ = +1.50%, VPI elevation 870.00 ft at station 22 +00, and a fixed elevation 874.00 ft at station 20 + 50. Part A Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations. Give the elevations in order of increasing X. Express your answers in feet to five significant figures separated by commas. ΑΣΦΗΤΗ Submit vec Elev = 874.00,874.39,874.79,872.00,869.21,868.81,868.42,868.03 ft Provide Feedback Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining ? Next >
A 500-ft curve, grades of g₁ = +2.00% and g2 = -2.50%, VPI at station 96+80, and elevation 845.260 ft, stakeout at full stations. Part A Determine the elevation at the high point of the curve. Express your answer in feet to six significant figures. Elev = Submit Part B AΣo↓ vec Request Answer Determine the station at the high point of the curve. O 97+12.77 O 96+13.33 O 96+52.22 O 97+96.66 ? ft
IOT is the vertical distance between which of ?the following two curves Recession curve and storage curve A Recession curve and Advance curve Depletion curve and advance curve .C None of these options .D
A-2.50% grade meets a +1.75% grade at station 44+25 and elevation 3385.74 ft, 400-ft curve, stakeout at half stations. Part A Determine the elevation at the low point of the curve Express your answer in feet to six significant figures. ΠΗΓΙΑΣΦ Elev = + ft
Item 2 Grades of g₁ = -2.50% and g₂ = +1.50%, VPI elevation 856.00 ft at station 22 +00, and a fixed elevation 860.00 ft at station 20 + 50. Part A Elev = Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations. Give the elevations in order of increasing X Express your answers in feet to five significant figures separated by commas. Submit Provide Feedback 17| ΑΣΦ. 41 Request Answer vec ? 2 of 5 ft Review Next >
A -1.10% grade meets a +0.60% grade at station 36+00 and elevation 800.00 ft. The +0.60 grade then joins a +2.40 grade at station 39+00. Determine the elevation at the low point of the curve. Express your answer in feet to six significant figures. 15. ΑΣΦ Elev = Submit Part B Request Answer Determine the station at the low point of the curve. 35+40.763 36+44.763 38+42.763 vec 36+42.763 D ? ft
Grades of +3.00% and -2.00%, sight distance 520 ft, h₁ = 3.50 ft and h₂ = 2.50 ft. Part A What is the minimum length of a vertical curve to provide a required sight distance for the conditions given? Express your answer in feet to five significant figures. L= Submit 7. ΑΣΦ 41 Request Answer vec 6 ? ft
Given: Stationing B= 18 + 685 Stationing C= 19 + 125 Tangent Lines: AB: Azim= 224° 24' BC: Azim= 264° 29' CD: Azim= 3150 28' A proposed highway curve is to connect these three tangents. Find: Radius of simple curve that connects these tangents. b. Sta PC. c. Length of the curve from PC to PT. a.
Assignment 3: Vertical Curve Design Question 2 The reduced level at the intersection of a rising gradient of P % and a falling gradient of Q % on a proposed road is XX.XX m. Given that K value is KK. The throught chainage of the intersection point is YYYY.YY m and proposed vertical curve is to have equal tangent. As a civil engineering you are required to prepare the following vertical curve design calculations: a) The through chainage of the points of the vertical curve if the minimum required length is to be used (Lv) and the vertical curve setting out data at 20 metres interval. b) The chainage and reduced level of the highest point on the curve. c) Through chainage at highest point was located exactly under a bridge, if the RL of soffit is SS.SS m, calculate the headroom based on proposed vertical curve design.

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