Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements shown below. A -3.40% grade meets a +2.75% grade at station 95+00 and elevation 1320.64 ft. Length of first curve 400 ft., second curve 600 ft. Match the correct elevation to the appropriate Station Value. Group of answer choices Sta. 91+00 (BVC) [ Choose ] Sta. 92+00 [ Choose ] Sta. 93+00 [ Choose ] Sta. 94+00 [ Choose

Q: A-2.40% grade meets a +1.50% grade at station 44+25 and elevation 3386.96 ft, 400-ft curve, stakeout…

A: The initial grade of the curve = -2.4% The final grade of the curve = +1.5% The station of point of…

Q: The tangents for a D = 4º30' circular curve (arc definition) meet at PI Sta 34+18.19 and the…

A: Degree of Curve = 4°30'PI of Station = 34+18.19Deflection angle (I) = 25°48'

Q: 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00%, Pl at station 96 + 80 and elevation 835.26 ft,…

A: g1=+2.5%g2= -3.00%L=500ftVPI station =96+80Elevation= 835.26ft

Q: What is the length of the curve, G1, highest point of curve, and the elevation of the highest point…

A: To find : Length of the curve, G1, highest point of curve, and the elevation of the highest point on…

Q: B-Unequal-Tangent Parabolic (Vertical) Curve: Example: A grade g1 of -2% intersects g2 of +1.6% at a…

A: Solution: Point A STA 85 + 00: Elev. = 743.24+2(2) = 747.24' Point B STA 90 + 00: Elev. =…

Q: A −2.50% grade meets a +1.75% grade at station 44+25 and elevation 3388.42 ft, 400-ft curve,…

A: The elevations and grades at the beginning and end of the curve need to be determined.  g1= -2.5%…

Q: An equal-tangent crest curve connects a +2.0% and a-1.0% grade. The PVC is at station + 670 and the…

A: The curve length will be: Lm=2×100station2 of PVI-station1 of PVCLm=200(1+790-1+670)      =240 ft

Q: A vertical parabolic curve has its PVI at station 18 + 50.00 and elevation 69.32. The grade of the…

A: In a vertical curve,PVC is the point of vertical curve.PVT is the point of vertical tangency.PVI is…

Q: Given the data of a compound curve with station of PI - 3+020, I₁-24°, D₁-6°, I₂-30° and D₂-7°,…

A: Sketch of the curve is given below with labelling and elements of the curve.

Q: 1. IN A CERTAIN ROAD CONSTRUCTION IS UNDERTAKEN DPWH, IT WAS DECIDED TO CONNECT A FORWARD TANGENT OF…

A:

Q: 1  (a) Compute curve elevations and offsets from tangents at 25 m intervals, including full…

A: Length of curve= L = 350m Upward grade (g1) = +2.7% Downward grade (g2) = -1.5% P.I station= 150+00,…

Q: A +3.0 percent grade intersects a - 2.0 percent grade at station 3 + 20 and at an elevation of…

A: The expression to calculate the station of the PVC is given by, Station of PVC=Station of PVI-L2…

Q: 18. An incoming grade of +3.00% meets an existing grade of -1.50% at a PVI having station 18+00 &…

A: Incoming grade, Existing grade, PVI stationElevation of PVI, Station of street, Elevation of street,…

Q: A +2.50% grade sets a -1.75% grade at station 44+25 and elevation 386.96 ft, 400ft curve, stakeout…

A: Solution: Computation of grades and distances in stations perpendicular…

Q: Compute full-station elevations for an unequal-tangent vertical curve to fit the requirements below.…

A: Grade, g1=+2.25% Grade, g2=+3.75% Station at VPI, 62+00 Elevation at VPI, EVPI=838 ft L1=700 ft,…

Q: A parabolic vertical curve connects a +3.5% grade with a -5.0% grade on a rural highway at section…

A: To calculate the location and elevation of the PVC (Point of Vertical Curvature) and PVT (Point of…

Q: 7.5% grade is followed by a 1.225% grade intersecting at Sta. 15+750, with an elevation of 395.5 m.…

A:

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

A:

Q: A +3% grade meets a -2% grade at station 60+50 and elevation 850.25ft, 1000 ft curve, stakeout at…

A: In transportation engineering or survey, the curve is classified as horizontal and vertical curves,…

Q: The following are offsets measured from a random line to a curve boundary 9.6, 12.4, 5.8, 7.0, 4.2.…

A:

Q: A 3% ascending grade meets a descending grade at the vertex at sta. 20+100 and at elevation 120 m.…

A: Given:- Ascending grade = 3% Station of vertex = 20 + 100 Elevation of vertex = 120 m Elevation of…

Q: Assume that a metric curve will be used at a PI whereA = 8° 24' Assume also that the station of the…

A: R= 900 m ∆=8°24' PI= 6+427.464 m Length of long chord= 2R sin∆2= 2*900*sin 4°12'=131.829 m Length of…

Q: take out a 200 ft spiral curve that transitions into a 60 00’ circular curve (arc definition).  PI…

A: The radius of the spiral curve- R=5729.58DR=5729.586°R=954.93° The spiral angle-…

Q: D] Calculate the centerline elevations for PVC, VPI, PVT, station 32+00, and turning point (highest…

A: Consider the free body diagram,;

Q: NEED ASAP SOLUTION. PLOT CURVE A vertical summit curve is having tangents which intersects at point…

A: PVCSTATION=PVISTA-L212500.65=12609.84-L2L=218.38mPVCELV=PVIELV-g1L2115.52=139.82-g1×218.382g1=22.254…

Q: A 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00 %, VPI at station 96 + 80 and elevation 851.26…

A: The initial grade of the curve = 2.5%The final grade of the curve = -3.0%The station of point of…

Q: A simple horizontal curve of radius 350 ft connects two tangents that form an intersection angle of…

A:

Q: (Computing a Vertical Curve) Initial Data: L = 80m, g1 = - 4.5%, g2 = + 3.2%, PVI at 4 + 60 with…

A:

Q: A +2.50% grade sets a -1.75% grade at station 44+25 and elevation 386.96 ft, 400ft curve, stakeout…

A: Given :

Q: Vertical highway curve: Given PVI at 128 + 00, L = 1,000 ft, g1 = -5%, g2 = +4%, and PVI elevation =…

A:

Q: Compute full-station elevations for an unequal-tangent vertical curve to fit the requirements below.…

A:

Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:- The initial grade of the curve = +1.512% The final grade of the curve = -1.785% The station…

Q: Field conditions require a highway curve to pass through a fixed point. Compute a suitable…

A:

Q: A-3% grade us connected to a +1.0% grade by means of 180m vertical curve. The point of intersection…

A: Length of curve= 180m Grades: g1 =-3%, g2=1%

Q: urve, grades of gl +2.50% and g2 = -2.50% %3D %3D vation 855.26 ft, stakeout at full stations. n…

A: G1 = 2.5 % G2  = -2.5 % PVI Station = (96+80) PVI elevation = 855.26 ft Length of curve L = 500 ft

Q: Grades of g₁ = -1.00% and g2 = +3.00 %, VPI elevation 750.00 ft at station 30+00. Fixed elevation…

A: g1= -1%g2= +3%PVI Elevation = 750 ft and station = 30+00Fixed elevation, y = 753 ft and station…

Q: IN A CERTAIN ROAD CONSTRUCTION IS UNDERTAKEN DPWH, IT WAS DECIDED TO CONNECT A FORWARD TANGENT OF 3%…

A:

Q: a) In a vertical curve a -1.5% grade intersects a +2.5% grade at station 475+00 with an elevation of…

A: Calculation of various parts or questions  Or vertical sag curve###

Q: 2. A 500 ft long equal-tangent crest vertical curve connects tangents that intersect at station…

A: I have solved as per your demand question number 2 only please go through it i have solved with…

Q: For the curve above, (an equal- tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI…

A:

Q: Grades of g = -2.50% and 92 = +1.50 %, VPI elevation 854.00 ft at station 22 +00, and a fixed…

A: The initial grade (g1) = -2.50%The initial grade (g2) = + 1.50%The elevation of PVI = 854 ftThe…

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