Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the requirements shown below. A -3.40% grade meets a +2.75% grade at station 95+00 and elevation 1320.64 ft. Length of first curve 400 ft., second curve 600 ft. Match the correct elevation to the appropriate Station Value. Group of answer choices Sta. 91+00 (BVC) [ Choose ] Sta. 92+00 [ Choose ] Sta. 93+00 [ Choose ] Sta. 94+00 [ Choose

Q: The tangents for a D = 4º30' circular curve (arc definition) meet at PI Sta 34+18.19 and the…

A: Degree of Curve = 4°30'PI of Station = 34+18.19Deflection angle (I) = 25°48'

Q: PROBLEM 6: A highway engineer must stake a symmetrical vertical curve where an entering grade of…

A: PVCELV=PVIELV-g1L2PVCelv=140.36-0.008×1202PVCelv=139.88mPVTELV=PVIELV+g2L2PVTelv=140.36-0.4×1202PVTe…

Q: A curve with a -6% downgade intersects an upward slope of +2%. The elevation at the intersection of…

A: To Find :- station of EVC

Q: A 500-ft curve, 9₁ = -2.00%, 9₂ = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500ftPvi elevation = 5388.26ftPvi station = 98+10To find:Elevations

Q: B-Unequal-Tangent Parabolic (Vertical) Curve: Example: A grade g1 of -2% intersects g2 of +1.6% at a…

A: Solution: Point A STA 85 + 00: Elev. = 743.24+2(2) = 747.24' Point B STA 90 + 00: Elev. =…

Q: A grade of -1.2% joins a grade of 1.8% at station 23+40 which has an elevation of 209.04 ft.…

A:

Q: A −2.50% grade meets a +1.75% grade at station 44+25 and elevation 3388.42 ft, 400-ft curve,…

A: The elevations and grades at the beginning and end of the curve need to be determined.  g1= -2.5%…

Q: In Idaho Spring, Colorado, an existing tunnel on I-70 (Veterans Memorial Tunnel, Figure 1) is to be…

A: Data given Elevation tunnel floor = 1500 ft Elevation of bridge deck = 1540 ft Station  PVC of sag…

Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:-The initial grade of the curve = +1.512%The final grade of the curve = -1.785%The station of…

Q: 1  (a) Compute curve elevations and offsets from tangents at 25 m intervals, including full…

A: Length of curve= L = 350m Upward grade (g1) = +2.7% Downward grade (g2) = -1.5% P.I station= 150+00,…

Q: A +3.0 percent grade intersects a - 2.0 percent grade at station 3 + 20 and at an elevation of…

A: The expression to calculate the station of the PVC is given by, Station of PVC=Station of PVI-L2…

Q: Given an equal tangent vertical curve, in feet, with the following known information: STA A…

A: Station of beginning of curve (A) = 15+00Elevation of point A, ElevA =80 feetLength of Curve, L=…

Q: 18. An incoming grade of +3.00% meets an existing grade of -1.50% at a PVI having station 18+00 &…

A: Incoming grade, Existing grade, PVI stationElevation of PVI, Station of street, Elevation of street,…

Q: A +2.50% grade sets a -1.75% grade at station 44+25 and elevation 386.96 ft, 400ft curve, stakeout…

A: Solution: Computation of grades and distances in stations perpendicular…

Q: Compute full-station elevations for an unequal-tangent vertical curve to fit the requirements below.…

A: Grade, g1=+2.25% Grade, g2=+3.75% Station at VPI, 62+00 Elevation at VPI, EVPI=838 ft L1=700 ft,…

Q: Given the following vertical curve data: g1 = -1%; g1 = +3%; design speed (V) = 80km/h PVI @ 1+300;…

A: Calculate the length of curve using k-value

Q: A parabolic vertical curve connects a +3.5% grade with a -5.0% grade on a rural highway at section…

A: To calculate the location and elevation of the PVC (Point of Vertical Curvature) and PVT (Point of…

Q: Compute full-station elevations for an unequal- tangent vertical curve to fit the requirements…

A: Grade, Grade, Station at VPI, Elevation at VPI, To find:             (a) Elevations from station…

Q: Item 2 Grades of g₁ = -2.50% and 92 = +1.50 %, VPI elevation 856.00 ft at station 22 +00, and a…

A: g1= -2.50%g2= + 1.50%PVI Elevation = 856 ftat 20+50 and y= 860 ft

Q: A -1.10% grade meets a +0.60% grade at station 36+00 and elevation 800.00 ft. The +0.60 grade then…

A: Grade, g1 = +2.40Grade, g2 = +0.60Elevation = 800.00 ft

Q: A sag curve has a length c (PVI) 475+00 at an elevat 478+00 470+00 472+50 477+50

A:

Q: as of ₁-2.50% and 9₂ +1.50 %, VPI elevation 856.00 ft at station 22 +00, and a foxed elevation…

A: g1= -2.50% g2= + 1.50% PVI Elevation = 856 ft at 20+50 and y= 860 ft

Q: 2.50% grade meets a +1.75% grade at station 44+25 and elevation 3385.74 ft, 400-ft curve, stakeout…

A: The elevations and grades at the beginning and end of the curve need to be determined. We will call…

Q: elevation 854.00 ft at station 20 + 50. Field conditions require a highway curve to pass through a…

A:

Q: A +3% grade meets a -2% grade at station 60+50 and elevation 850.25ft, 1000 ft curve, stakeout at…

A: In transportation engineering or survey, the curve is classified as horizontal and vertical curves,…

Q: A 850-ft equal-tangent creat vertical cuve has its PVC at station 102+00 and elevation 1000 ft. The…

A: g1 = 3.5%g2 = - 3 %Length of curve (L) = 850 ft

Q: Field conditions require a highway curve to pass through a fixed point. Compute a suitable…

A: g1= -2.50%g2= + 1.50%PVI Elevation = 868 ft and station = 22+00Fixed elevation, y = 872 ft and…

Q: take out a 200 ft spiral curve that transitions into a 60 00’ circular curve (arc definition).  PI…

A: The radius of the spiral curve- R=5729.58DR=5729.586°R=954.93° The spiral angle-…

Q: D] Calculate the centerline elevations for PVC, VPI, PVT, station 32+00, and turning point (highest…

A: Consider the free body diagram,;

Q: A-1.10% grade meets a +0.60% grade at station 36+00 and elevation 800.00 ft. The +0.60 grade then…

A: The station of the intersection of grades -1.10% & +0.60% = 36+00The elevation of the…

Q: Given an equal tangent vertical curve, in feet, with the following known information: STAA…

A:

Q: 25. For a preliminary vertical alignment of a roadway, the straight tangent sections are established…

A:

Q: 103+51.05 103+53.01 103+47.56 103+49.89

A: 103 + 51.05

Q: Adowngrade of 3.2% meets a rising grade of4.6%at station 73+180,where the elevation is 998 m.Asag…

A: Given:- A downgrade of the curve = 3.2% A rising grade of the curve = 4.6% The station of point of…

Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:- The initial grade of the curve = +1.512% The final grade of the curve = -1.785% The station…

Q: iven the same vertical alignment connecting a -4% grade with a +2% grade vith the PVC station at…

A:

Q: upan For a sag vertical curve shown in the figure bel- Sta. 7+00 -2.3%

A:

Q: urve, grades of gl +2.50% and g2 = -2.50% %3D %3D vation 855.26 ft, stakeout at full stations. n…

A: G1 = 2.5 % G2  = -2.5 % PVI Station = (96+80) PVI elevation = 855.26 ft Length of curve L = 500 ft

Q: Grades of g₁ = -1.00% and g2 = +3.00 %, VPI elevation 750.00 ft at station 30+00. Fixed elevation…

A: g1= -1%g2= +3%PVI Elevation = 750 ft and station = 30+00Fixed elevation, y = 753 ft and station…

Q: IN A CERTAIN ROAD CONSTRUCTION IS UNDERTAKEN DPWH, IT WAS DECIDED TO CONNECT A FORWARD TANGENT OF 3%…

A:

Q: Grades of g₁ = -0.75% and 9₂ = +3.25%, VPI elevation 750.00 ft at station 30+00. Fixed elevation…

A: NOTE : Since you have asked multiple questions, we will solve the first question for you. If you…

Q: a) In a vertical curve a -1.5% grade intersects a +2.5% grade at station 475+00 with an elevation of…

A: Calculation of various parts or questions  Or vertical sag curve###

Q: For the curve above, (an equal- tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI…

A:

Q: Given a crest vertical curve of length 523, with a PVC at elevation 1,016, connecting a grade 1% to…

A: The elevation of PVC = 1016The vertical curve consists of grades 1% and -0.5%The length of the curve…

Q: 2. Compute by hand and tabulate station elevations and the 1st and 2nd differences for an equal…

A: Data given G1 =+3.5% G2 =-4 % Station PVI = 12+65 Elevation PVI = 300 ft Length of curve, L = 750 ft…

Q: Given an equal tangent vertical curve, in feet, with the following known information: • STA A…

A:

Electronic Spreadsheet

Tabular listing has many advantages ranging from time management to efficient scheduling of tasks. Electronic spreadsheets allow the user to tabulate and analyze data, using its easy-to-use interface. An electronic spreadsheet is a staple application used among accountants, management staff, and IT professionals. It is used in various sectors worldwide for data management. An electronic spreadsheet is a system and computer software that could be used to do numerical computations automatically. Spreadsheet application programs are often organized as a table with rows and columns. Each row and column intersect to form a cell, which may be used to store data. These data can take the form of a written label, a number, or a formula that combines information from other cells.