1  (a) Compute curve elevations and offsets from tangents at 25 m intervals, including full stations, for a 350 m vertical curve joining a +2.70% grade with a -1.50% grade. Assume the P.I. is at station 150 + 00 and elevation 25.00 m. Results should be in tabular form, with columns for stations, tangent elevations, offsets, and curve elevations starting at the BVC and ending at the EVC of the curve. (b) Plot the profile for the curve data in part a

Q: The tangents for a D = 4º30' circular curve (arc definition) meet at PI Sta 34+18.19 and the…

A: Degree of Curve = 4°30'PI of Station = 34+18.19Deflection angle (I) = 25°48'

Q: Q2) A circular curve is to join two tangents that intersect at an angle of 23°18' at PI station…

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Q: A 500-ft curve, 9₁ = -2.00%, 9₂ = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500ftPvi elevation = 5388.26ftPvi station = 98+10To find:Elevations

Q: Q2) A circular curve is to join two tangents that intersect at an angle of 23°18' at PI station…

A: Answer We are given Angle of Intersection ∆ = 23o18' Station at PI = (40+55.8) External distance E =…

Q: A preliminary highway location has been made by locating tangents. Deflection angles have been…

A:

Q: A 500-ft curve, 9₁ = -2.00%, g2 = +3.00%, VPI station = 98+10, VPI elevation = 5388.26 ft, stakeout…

A: g1 = -2.00%g2= +3.00%L = 500ftVPI station, Elevation of VPI, To find: Elevation of full stations.

Q: A vertical summit curve is having tangents which intersects at point Pl at Station 12+584.57 and…

A: Given Data:PVI=12+584.57Elv=139.32mgrade=-5.25%PVC=12+527.65Elv=122.32m

Q: Given the data of a compound curve with station of PI - 3+020, I₁-24°, D₁-6°, I₂-30° and D₂-7°,…

A: Sketch of the curve is given below with labelling and elements of the curve.

Q: In Idaho Spring, Colorado, an existing tunnel on I-70 (Veterans Memorial Tunnel, Figure 1) is to be…

A: Data given Elevation tunnel floor = 1500 ft Elevation of bridge deck = 1540 ft Station  PVC of sag…

Q: With a radius of 280 meters and  distance from Pc to Pt along the curve is 240 meters. - Compute…

A: Radius = 280mPC to PT  distance = 240m

Q: The tangent through PC and PT intersects at Station 100+280, the length of chord from PC to PT is…

A: Given data, Station of point of intersection = 100+280 = 100280 m Length of long chord L = 80 m…

Q: conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent…

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Q: n angle of 2 346° respec e of the new ec" new curve.

A: SOLUTION OF QESTION NUMBER 6 BELOW

Q: A +2.50% grade sets a -1.75% grade at station 44+25 and elevation 386.96 ft, 400ft curve, stakeout…

A: Solution: Computation of grades and distances in stations perpendicular…

Q: A parabolic vertical curve connects a +3.5% grade with a -5.0% grade on a rural highway at section…

A: To calculate the location and elevation of the PVC (Point of Vertical Curvature) and PVT (Point of…

Q: Given a 520m common tangent of a compound horizontal curve, determine the length of the second curve…

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Q: A reversed curve with diverging tangents is to pass through three lines to form a centerline of a…

A:

Q: Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the…

A: Based on the given data let us draw the below figure

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

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Q: A backward tangent having a slope of 7% intersects the forward tangent having a slope -4% at…

A:

Q: 1. IN A CERTAIN ROAD CONSTRUCTION IS UNDERTAKEN DPWH, IT VWAS DECIDED TO CONNECT A FORWARD TANGENT…

A:

Q: A highway circular curve with Da 2°30',I10°30', and PI station 36+44.50 ft. Assume…

A: The given data is shown below: Da=2°30'I=10°30'PI station=36+44.50 ft

Q: A horizontal circular curve is being designed with the point of tangent (PT) located at station…

A:

Q: Problem 1. Two tangents having an azimuth of 265° and 289° respectively intersect at station…

A: We have find new tangent distance, radius of the new curve and stationing of new PC. in this…

Q: A +3% grade meets a -2% grade at station 60+50 and elevation 850.25ft, 1000 ft curve, stakeout at…

A: In transportation engineering or survey, the curve is classified as horizontal and vertical curves,…

Q: The following are offsets measured from a random line to a curve boundary 9.6, 12.4, 5.8, 7.0, 4.2.…

A:

Q: Assume that a metric curve will be used at a PI whereA = 8° 24' Assume also that the station of the…

A: R= 900 m ∆=8°24' PI= 6+427.464 m Length of long chord= 2R sin∆2= 2*900*sin 4°12'=131.829 m Length of…

Q: D] Calculate the centerline elevations for PVC, VPI, PVT, station 32+00, and turning point (highest…

A: Consider the free body diagram,;

Q: A circular curve  is to be set out by bearing and distance methods from two control points. During…

A: Given,Bearing TI = 110°17'16"Point T = 1359.67 mE, 2165.44 mN   Step 1: Calculate the coordinates of…

Q: Problem 2: A compound curve laid on their tangent has the following data: h = 35° I2 = 42 ° D1= 3 °…

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Q: A simple horizontal curve of radius 350 ft connects two tangents that form an intersection angle of…

A:

Q: A +2.50% grade sets a -1.75% grade at station 44+25 and elevation 386.96 ft, 400ft curve, stakeout…

A: Given :

Q: On a rail road line, two tangents that intersects at station 10 + 236 so as to form an angle of 33°…

A: Two tangents that intersects at station 10 + 236  central angle = 16° D1 = 5.90

Q: Compute full-station elevations for an unequal-tangent vertical curve to fit the requirements below.…

A:

Q: Civil Engineering Imagine a two lane highway segment with crown slopes of -1.3%and the start of the…

A: kbjjnoj nkokjpojpjpwjjwpj;k;kjlkjl kejlkejejnjrrhrheekkeje ejnelkknelkljelklene klknelnelkn…

Q: urve, grades of gl +2.50% and g2 = -2.50% %3D %3D vation 855.26 ft, stakeout at full stations. n…

A: G1 = 2.5 % G2  = -2.5 % PVI Station = (96+80) PVI elevation = 855.26 ft Length of curve L = 500 ft

Q: Grades of g₁ = -1.00% and g2 = +3.00 %, VPI elevation 750.00 ft at station 30+00. Fixed elevation…

A: g1= -1%g2= +3%PVI Elevation = 750 ft and station = 30+00Fixed elevation, y = 753 ft and station…

Q: For a highway curve with D₁ = 5°00', I = 20°30', and Pl station = 63+ 25.53 ft, calculate the…

A: Step 1:Step 2:Step 3:Step 4:Step 5:Step 6:

Q: IN A CERTAIN ROAD CONSTRUCTION IS UNDERTAKEN DPWH, IT WAS DECIDED TO CONNECT A FORWARD TANGENT OF 3%…

A:

Q: Situation I: A 6' simple curve connects two tangents that intersect at an angle of 42". If the PC…

A: Given  Degree of curve 1 = 6°  Shift=20 m

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.