Grades of g1 = -2.50% and g2 = +1.50%, VPI elevation 868.00 ft at station 22 +00, and a fixed elevation 872.00 ft at station 20 + 50.

Q: A-2.40% grade meets a +1.50% grade at station 44+25 and elevation 3386.96 ft, 400-ft curve, stakeout…

A: The initial grade of the curve = -2.4% The final grade of the curve = +1.5% The station of point of…

Q: 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00%, Pl at station 96 + 80 and elevation 835.26 ft,…

A: g1=+2.5%g2= -3.00%L=500ftVPI station =96+80Elevation= 835.26ft

Q: Problem #5 A compound horizontal curve is composed of 2 circular curves. The end of curve 1 is the…

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Q: Given the data of a compound curve with station of PI - 3+020, I₁-24°, D₁-6°, I₂-30° and D₂-7°,…

A: Sketch of the curve is given below with labelling and elements of the curve.

Q: With a radius of 280 meters and  distance from Pc to Pt along the curve is 240 meters. - Compute…

A: Radius = 280mPC to PT  distance = 240m

Q: s when laying out a curve with the instrument set at the beginning of the curve.

A: In order to create a progressive shift in direction, curves are regular bends built into…

Q: conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent…

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Q: ● A back tangent with azimuth 298° meets a forward tangent with azimuth 170°. What is the…

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Q: The angle of intersection of a simple curve is 24֯. A point Q on the curve is to be established such…

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Q: Grades of g -2.50% and 9 +1.50 %, VPI elevation 856.00 ft at station 22+00, and a fixed elevation…

A: The initial grade (g1) = -2.50% The initial grade (g2) = + 1.50% The elevation of PVI = 856 ft The…

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

A:

Q: A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 162.657 m, 180-m curve, stakeout…

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Q: A 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00 %, VPI at station 96 + 80 and elevation 851.26…

A: The initial grade of the curve = 2.5%The final grade of the curve = -3.0%The station of point of…

Q: Given the following information for a compound curve that Leads with short curve o | = 98°48'13" Is…

A:

Q: Given the Following information for a compound curve that Leads with short curve o | = 105°58'12" TL…

A: Given I = 105°58'12" TL = 2641.08 ft Ts = 2110.17 ft DL = 2°30' (chord definition) To Determine…

Q: urve, grades of gl +2.50% and g2 = -2.50% %3D %3D vation 855.26 ft, stakeout at full stations. n…

A: G1 = 2.5 % G2  = -2.5 % PVI Station = (96+80) PVI elevation = 855.26 ft Length of curve L = 500 ft

Q: For a highway curve with D₁ = 5°00', I = 20°30', and Pl station = 63+ 25.53 ft, calculate the…

A: Step 1:Step 2:Step 3:Step 4:Step 5:Step 6:

Q: Grades of g = -2.50% and 92 = +1.50 %, VPI elevation 854.00 ft at station 22 +00, and a fixed…

A: The initial grade (g1) = -2.50%The initial grade (g2) = + 1.50%The elevation of PVI = 854 ftThe…

Q: Problem 3: The angle of intersection of a simple curve is l=53.13 ° and the length of curve is…

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