A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 162.657 m, 180-m curve,stakeout at 30-m increments.List station elevations, including BVC and EVC, for an equal-tangent parabolic curve for thedata given. Give the elevations in order of increasing X.Express your answers in meters to six significant figures separated by commas.

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Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Horizontal Curve Given: Radius (R) = 1654.35' Degree of Curve (Daº) = 03°-27¹-48" PC Station = 14 + 27.62 Chord distance to Station 16 +00= ? 172.30' 170.10' 174.59' 168.75'
1. Given are the stations and elevations of a proposed symmetrical parabolic highway curve. POINT A B с ELEVATION (m) 93.60 90.00 96.48 STATION 6+075 6+255 (PI) 6+435 Note: Lines AB and BC are the tangent lines of the proposed highway curve. The curve will clear a boulder at Sta. 6+276, and the elevation of the tip of the boulder is 92.65m. Solve for the ff: a. length of the symmetrical curve b. stationing and elevation of PC c. A circular pipe culvert is to be laid out as part of road drainage requirements. If the elevation of the invert of the culvert is 90.25 m., determine the volume of earthworks needed to cover the culvert considering a 20% shrinkage factor for the backfill. The culvert has an inner radius of 0.4 m and thickness of 0.1 m. Consider 1 m width of the road section. 2. Suppose that during the construction of the symmetrical curve in problem #1, it was discovered that left side of the grade intersection falls on a rocky terrain. To avoid additional cost of excavation,…
For items 1, and 2: A vertical parabolic curve of 260-m length has a back-tangent of -4.2% grade and a forward tangent of +3.0% which intersect at Station 11 + 488.00 with elevations 20.80 meters. a.) If cross-drainage pipes will be installed, determine the pipes' stationing. Provide the answer in kilometers e.g. 11,900 (instead of 11+900). 11+509.67
please resolve this! SURVEYING (UPVOTE WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTIONS AND DIAGRAMS *IF NECESSARY* LEGIBLY. NO LONG EXPLANATION IS NEEDED. ANSWER IN 2 DECIMAL PLACES AND BOX THE FINAL ANSWER. PLEASE ANSWER ALL.) The long chord from PC to PT of a compound curve is 320m long, and the angles it makes with the first and third tangents are 14° and 16°, respectively. If the common tangent is parallel to the long chord, solve the following: a. The radius of the first curve (R1). b. The radius of the second curve (R2). c. If station of PC is 8+200, compute the station of PT.
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SHOW SOLUTION AND DRAWING LABEL THE POINTS ACCORDINGLY
A-2.60% grade meets a +1.70% grade at station 44+25 and elevation 3387.96 ft, 400-ft curve, stakeout at half stations. Part A Tabulate station elevations for an equal-tangent parabolic curve for the data given above. Express your answers in feet to six significant figures separated by commas in order of increasing station numbers. Elev = Submit ΑΣΦ ↓↑ Request Answer vec ? ft
A piece of land ABCDEA which lies at the corner of Cedar and Elm streets has the following data. The radius of the circular curve is 310.00. a) Find the co-ordinates of points A, B, C, D and E, if the x-axis passes through line AE and the y- axis through point B (see diagram). The co-ordinates of origin O are 0,0. b) Calculate the area of this piece of land in hectares. Figure 1: Land area at the corner of Elm and Cedar streets.
TOPIC: SURVEYING (REVERSED CURVE) Please help me solve this problem with a detailed solution. Thank you tutor and god bless!
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Please solve this problem using Arc Basis. Please include illustrations and sketches in the solution. I need this As Soon As Possible. Thank you!

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