A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 162.657 m, 180-m curve, stakeout at 30-m increments. List station elevations, including BVC and EVC, for an equal-tangent parabolic curve for the data given. Give the elevations in order of increasing X. Express your answers in meters to six significant figures separated by commas.

Q: A-2.40% grade meets a +1.50% grade at station 44+25 and elevation 3386.96 ft, 400-ft curve, stakeout…

A: The initial grade of the curve = -2.4% The final grade of the curve = +1.5% The station of point of…

Q: Compute the passing sight distance available given a 435-ft curve, grades of g₁=+2.00% and 92 =…

A: Curve length, L = 435 fth1 = 3.25 fth2 = 4.50 ftg1 = 2 %g2 = -1.5 %VPI at station 96+80Elevation =…

Q: Problem #6 A reverse horizontal curve is composed of 2 circular curves. The end of curve 1 is the…

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Q: A 500-ft curve, 9₁ = -2.00%, 9₂ = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500ftPvi elevation = 5388.26ftPvi station = 98+10To find:Elevations

Q: Curves Question 9 What is the degree of the curve (in degree) for a radius of 573 m using chain of…

A: Given- Radius R=573 m chain length=20 m It is needed to find the degree of the curve.

Q: A 500-ft curve, grades of g₁ = +1.50 % and g₂ = -2.50%, VPI at station 96 + 80 and elevation 841.26…

A: The initial grade of the curve = 1.5%The final grade of the curve = -2.50%The station of point of…

Q: Given the following vertical curve data: g1 = -1%; g1 = +3%; design speed (V) = 80km/h PVI @ 1+300;…

A: Calculate the length of curve using k-value

Q: A 500-ft curve, 91 = -2.00%, g2 = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500 ftPVI elevation = 5388.26 ftPVI station = 98+10

Q: A 500-ft curve, 9₁ = -2.00%, g₂ = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: Given data: Elevation of PVC Station of PVC PVT station

Q: A500-ft curve, grades of g +2.50% and 2 50% VPI at station 96 80 and elevation 839 26 ft, stakeout…

A: Length of curve, Grade 1, Grade 2, VPI station, Elevation of VPI, To find: The elevation of full…

Q: A 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00 %, VPI at station 96 + 80 and elevation 851.26…

A: The initial grade of the curve = 2.5%The final grade of the curve = -3.0%The station of point of…

Q: 25. For a preliminary vertical alignment of a roadway, the straight tangent sections are established…

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Q: upan For a sag vertical curve shown in the figure bel- Sta. 7+00 -2.3%

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Q: urve, grades of gl +2.50% and g2 = -2.50% %3D %3D vation 855.26 ft, stakeout at full stations. n…

A: G1 = 2.5 % G2  = -2.5 % PVI Station = (96+80) PVI elevation = 855.26 ft Length of curve L = 500 ft

Q: Compute and tabulate the data necessary to stake, by tangent offsets, the half- stations (ex. +50,…

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Q: the intersection curve (R = 35 ft) at Main Compute the length of arc. Determine the curb-line…

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Q: Grades of g₁ = -0.50% and 92 = +3.50 %, VPI elevation 750.00 ft at station 30+00. Fixed elevation…

A: Finding length and rate of grade change.