Grades of g₁ = -0.75% and 9₂ = +3.25%, VPI elevation 750.00 ft at station 30+00. Fixed elevation 753.00 ft at station 30 +00. Part A Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations. Give the elevations in order of increasing X. Express your answers in feet to five significant figures separated by commas.

Q: 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00%, Pl at station 96 + 80 and elevation 835.26 ft,…

A: g1=+2.5%g2= -3.00%L=500ftVPI station =96+80Elevation= 835.26ft

Q: Problem #6 A reverse horizontal curve is composed of 2 circular curves. The end of curve 1 is the…

A:

Q: Problem #5 A compound horizontal curve is composed of 2 circular curves. The end of curve 1 is the…

A:

Q: A curve with a -6% downgade intersects an upward slope of +2%. The elevation at the intersection of…

A: To Find :- station of EVC

Q: A 500-ft curve, 9₁ = -2.00%, 9₂ = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500ftPvi elevation = 5388.26ftPvi station = 98+10To find:Elevations

Q: A 500-ft curve, 9₁ = -2.00%, g2 = +3.00%, VPI station = 98+10, VPI elevation = 5388.26 ft, stakeout…

A: g1 = -2.00%g2= +3.00%L = 500ftVPI station, Elevation of VPI, To find: Elevation of full stations.

Q: 2. A simple curve of the proposed extension of Mantabahadra Highway have a direction of tangent AB…

A:

Q: Item 2 Grades of g₁ = -2.50% and 92 = +1.50 %, VPI elevation 856.00 ft at station 22 +00, and a…

A: g1= -2.50%g2= + 1.50%PVI Elevation = 856 ftat 20+50 and y= 860 ft

Q: Grades of +3.00% and -2.00%, sight distance 520 ft, h₁ = 3.50 ft and h₂ = 2.50 ft. Part A What is…

A:

Q: Compute and tabulate full-station elevations for an unequal-tangent vertical curve to fit the…

A: Based on the given data let us draw the below figure

Q: Two highway tangents intersect with a right intersection angle of 33*17' at station 73+61.28. If a…

A:

Q: A 500-ft curve, g₁ = -2.00%, 92 = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A:

Q: A 500-ft curve, 91 = -2.00%, g2 = +3.00 %, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: g1 = -2.00%g2= +3.00%L = 500 ftPVI elevation = 5388.26 ftPVI station = 98+10

Q: A 500-ft curve, grades of g₁ = +2.50% and 9₂ = -3.00%, VPI at station 96 + 80 and elevation 835.26…

A:

Q: as of ₁-2.50% and 9₂ +1.50 %, VPI elevation 856.00 ft at station 22 +00, and a foxed elevation…

A: g1= -2.50% g2= + 1.50% PVI Elevation = 856 ft at 20+50 and y= 860 ft

Q: A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 162.657 m, 180-m curve, stakeout…

A:

Q: elevation 854.00 ft at station 20 + 50. Field conditions require a highway curve to pass through a…

A:

Q: A 500-ft curve, 9₁ = -2.00%, g₂ = +3.00%, VPI station = 98 + 10, VPI elevation = 5388.26 ft,…

A: Given data: Elevation of PVC Station of PVC PVT station

Q: Field conditions require a highway curve to pass through a fixed point. Compute a suitable…

A: g1= -2.50%g2= + 1.50%PVI Elevation = 868 ft and station = 22+00Fixed elevation, y = 872 ft and…

Q: Grades of g₁ = -2.50% and 92 = +1.50%, VPI elevation 860.00 ft at station 22 +00, and a fixed…

A: To solve this problem, we need to calculate the elevations of an equal-tangent vertical curve given…

Q: A 500-ft curve, grades of g₁ = +2.50% and g₂ = -3.00 %, VPI at station 96 + 80 and elevation 851.26…

A: The initial grade of the curve = 2.5%The final grade of the curve = -3.0%The station of point of…

Q: Given an equal tangent vertical curve, in feet, with the following known information: STAA…

A:

Q: Grades of g₁ = -2.25% and 92 = +1.75 %, VPI elevation 750.00 ft at station 30 + 00. Fixed elevation…

A:

Q: upan For a sag vertical curve shown in the figure bel- Sta. 7+00 -2.3%

A:

Q: urve, grades of gl +2.50% and g2 = -2.50% %3D %3D vation 855.26 ft, stakeout at full stations. n…

A: G1 = 2.5 % G2  = -2.5 % PVI Station = (96+80) PVI elevation = 855.26 ft Length of curve L = 500 ft

Q: Grades of g₁ = -1.00% and g2 = +3.00 %, VPI elevation 750.00 ft at station 30+00. Fixed elevation…

A: g1= -1%g2= +3%PVI Elevation = 750 ft and station = 30+00Fixed elevation, y = 753 ft and station…

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