Gm,m; Two masses, m, and m2 are separated by a distance, r. The force of between the two masses is F. If r is halved, how would F change? 4F (4 times force) 1/4F (1/4 times the force) 2F (2 times the force) 1/2F (1/2 the force)
Gm,m; Two masses, m, and m2 are separated by a distance, r. The force of between the two masses is F. If r is halved, how would F change? 4F (4 times force) 1/4F (1/4 times the force) 2F (2 times the force) 1/2F (1/2 the force)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Gravitational Force Calculation**
The formula for the gravitational force (\( F_g \)) between two masses (\( m_1 \) and \( m_2 \)) separated by a distance (\( r \)) is given by:
\[
F_g = \frac{Gm_1m_2}{r^2}
\]
Where:
- \( F_g \) is the gravitational force.
- \( G \) is the gravitational constant.
- \( m_1 \) and \( m_2 \) are the masses.
- \( r \) is the distance between the centers of the two masses.
**Question:**
Two masses, \( m_1 \) and \( m_2 \), are separated by a distance, \( r \). The force of attraction between the two masses is \( F \).
If \( r \) is halved, how would \( F \) change?
**Options:**
- ○ \( 4F \) (4 times the force)
- ○ \( 1/4F \) (1/4 times the force)
- ○ \( 2F \) (2 times the force)
- ○ \( 1/2F \) (1/2 the force)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1357887-becf-4289-b67d-2b8f988a0b81%2F0f5fb4e8-4d76-4eaa-bd17-5a780922da0f%2Flovq03e_processed.png&w=3840&q=75)
Transcribed Image Text:**Gravitational Force Calculation**
The formula for the gravitational force (\( F_g \)) between two masses (\( m_1 \) and \( m_2 \)) separated by a distance (\( r \)) is given by:
\[
F_g = \frac{Gm_1m_2}{r^2}
\]
Where:
- \( F_g \) is the gravitational force.
- \( G \) is the gravitational constant.
- \( m_1 \) and \( m_2 \) are the masses.
- \( r \) is the distance between the centers of the two masses.
**Question:**
Two masses, \( m_1 \) and \( m_2 \), are separated by a distance, \( r \). The force of attraction between the two masses is \( F \).
If \( r \) is halved, how would \( F \) change?
**Options:**
- ○ \( 4F \) (4 times the force)
- ○ \( 1/4F \) (1/4 times the force)
- ○ \( 2F \) (2 times the force)
- ○ \( 1/2F \) (1/2 the force)
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