Series capacitors Combinations: 1. Select three resistors and measure their capacitance with the Fluke meter. C1 = 13.8nF C2 = 12.7 nF C3 = 3.38 nF (F: Farad - unit of capacitor; n: Nano- 1x 10-9 2. Using Equation 1 to calculate the equivalent capacitance 3. The measured the equivalent capacitance Ce is 2.34 nF 4. Compare the calculated value with the measured value, show the difference. Difference = calculated value-measured value

Series capacitors Combinations: 1. Select three resistors and measure their capacitance with the Fluke meter. C1 = 13.8nF C2 = 12.7 nF C3 = 3.38 nF (F: Farad - unit of capacitor; n: Nano- 1x 10-9 2. Using Equation 1 to calculate the equivalent capacitance 3. The measured the equivalent capacitance Ce is 2.34 nF 4. Compare the calculated value with the measured value, show the difference. Difference = calculated value-measured value

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter27: Capacitors And Batteries

Section: Chapter Questions

Problem 17PQ: A pair of capacitors with capacitances CA = 3.70 F and CB = 6.40 F are connected in a network. What...

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Concept explainers

Temperature Variance of Resistance

Electrical resistance or simply resistance is the property of a material that opposes the free flow of electrons through it. The total amount of resistance to the flow of charges (or current) is affected by many factors like the length of the conducting material, its cross-sectional area, resistivity, and temperature.

Question

please us information in image 1 to answer the questions in image 2

CAPACITANCE
When capacitors are connected in series, the equivalent capacitor is:
1/Ce=1/C1 + 1/C2 + ... (Equation 1)
When capacitors are connected in parallel, the equivalent capacitor is:
Ce = C1+ C₂+... (Equation 2)

Series capacitors Combinations:
1. Select three resistors and measure their capacitance with the Fluke meter.
C1 = 13.8nF C2 = 12.7 nF
C3 = 3.38 NF
(F: Farad - unit of capacitor; n: Nano- 1x 10-9
2. Using Equation 1 to calculate the equivalent capacitance
3. The measured the equivalent capacitance Ce is 2.34 nF
4. Compare the calculated value with the measured value, show the difference.
Difference = calculated value - measured value
5. Find percent error:
% error = (| calculated value-measured value|/ calculated value) * 100%

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