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A particle with a charge of +1.24x10-8 C is moving with instantaneous velocity = (-4.19 x 10¹ m/s)i + (-3.85 x 104 m/s)k. What is the force exerted on this particle by a magnetic field = (1. 20T)ĵ? → B 04 F = (6.68 × 10-4N)3 + (7.27 × 10-¹N)Ê F = (6.68 × 10-4N)i + (−7.27 × 10¯¹N)Ê F=(-6.68 x 10-4N)i + (-7.27 × 10-4N) F = (-6.68 × 10-N)3 + (7.27 × 10-N)Ê O O F = (-6.68 × 10-4N)i + (7.27 × 10-N)Ê

A particle with a charge of +1.24x10-8 C is moving with instantaneous velocity = (-4.19 x 10¹ m/s)i + (-3.85 x 104 m/s)k. What is the force exerted on this particle by a magnetic field = (1. 20T)ĵ? → B 04 F = (6.68 × 10-4N)3 + (7.27 × 10-¹N)Ê F = (6.68 × 10-4N)i + (−7.27 × 10¯¹N)Ê F=(-6.68 x 10-4N)i + (-7.27 × 10-4N) F = (-6.68 × 10-N)3 + (7.27 × 10-N)Ê O O F = (-6.68 × 10-4N)i + (7.27 × 10-N)Ê

College Physics
College Physics
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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F = (6.68 × 10-4N)3 + (7.27 × 10-N)k F (6.68 x 10-N)2+(-7.27 × 10-N) = F = (-6.68 × 10-4N)i + (−7. 27 × 10−4N)Ê F = (-6.68 × 10-N)ĵ + (7.27 × 10−4N)Ê 0→ F = (–6.68 × 10−4N)i + (7.27 × 10−4N)Ê F = (6.68 × 10−4N)i + (7.27 × 10−4N)Ê F = (–6.68 × 10−¹N)i + (−7. 27 × 10−¹N)Ê F = (6.68 × 10-4N) 3+ (−7. 27 × 10−¹N)Ê
Transcribed Image Text:F = (6.68 × 10-4N)3 + (7.27 × 10-N)k F (6.68 x 10-N)2+(-7.27 × 10-N) = F = (-6.68 × 10-4N)i + (−7. 27 × 10−4N)Ê F = (-6.68 × 10-N)ĵ + (7.27 × 10−4N)Ê 0→ F = (–6.68 × 10−4N)i + (7.27 × 10−4N)Ê F = (6.68 × 10−4N)i + (7.27 × 10−4N)Ê F = (–6.68 × 10−¹N)i + (−7. 27 × 10−¹N)Ê F = (6.68 × 10-4N) 3+ (−7. 27 × 10−¹N)Ê
A particle with a charge of +1.24x10-8 C is moving with instantaneous velocity V= = (-4. 19 x 10¹ m/s)i + (-3.85 x 104 m/s)k. What is the force exerted on this particle by a magnetic field B = (1. 20T)? → O F (6.68 x 10-4N)3 + (7.27 × 10-4N) - F = (6.68 × 10-4N)i + (−7.27 × 10-4N)Ê O F= (-6.68 × 10-4N)i + (−7. 27 × 10−¹N)Ê O F = (-6.68 × 10-4N)3+ (7.27 × 10-N)Ê F = (-6.68 × 10-4N)i + (7.27 × 10-4N)Ê
Transcribed Image Text:A particle with a charge of +1.24x10-8 C is moving with instantaneous velocity V= = (-4. 19 x 10¹ m/s)i + (-3.85 x 104 m/s)k. What is the force exerted on this particle by a magnetic field B = (1. 20T)? → O F (6.68 x 10-4N)3 + (7.27 × 10-4N) - F = (6.68 × 10-4N)i + (−7.27 × 10-4N)Ê O F= (-6.68 × 10-4N)i + (−7. 27 × 10−¹N)Ê O F = (-6.68 × 10-4N)3+ (7.27 × 10-N)Ê F = (-6.68 × 10-4N)i + (7.27 × 10-4N)Ê
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