Giver 3- Rod of length L centre of mass at distanu d Linzai elensky ९(X) 2 = 7 m/t

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Please provide a step by step process (in sentences) on how this was solve. Think of it as if you’re going to present this to the entire class
Giver 3-
Rod of length L
centre of mass at distanu d
Linzań dlenšiły
g(x)
Lineai density at right and S(L)
344
S(x) xx"
S(x)
= 20 kg/m
we have to find Linear density at pan't & from left end
L
= kxn
We
To Find k
3(+) = 20 kg/m
k
†(x) = ૨૦
2009
CM
x^
11
have to Find n and k
=
느릅니
2²
=
proportionality conslanu
P(x) = Lincar distanu
density
кли
20
L^
x
Linian
Transcribed Image Text:Giver 3- Rod of length L centre of mass at distanu d Linzań dlenšiły g(x) Lineai density at right and S(L) 344 S(x) xx" S(x) = 20 kg/m we have to find Linear density at pan't & from left end L = kxn We To Find k 3(+) = 20 kg/m k †(x) = ૨૦ 2009 CM x^ 11 have to Find n and k = 느릅니 2² = proportionality conslanu P(x) = Lincar distanu density кли 20 L^ x Linian
To find
centre of mais (CM) = [ @mse
(dm) x
Sdm
• Susixie de
CM =
L
f(x) dx
CM
CM
20
{x^"dx
20
L
(2) j^x^ de
dx
(n+1)
(n+2)
{
=
(201²), "
(n+1)
(n+₂)
22+1
"
3L.
042
nyl
x^
?
L
(2)
4 (n+1)
4n+ 4
D
stxatida
suxndx
3L
l
So combining
and O
Lencai density at distance x from left end
3(x) = 20 (=) ² kg/m
3L
BL
4
= 3 (n+2)
= 3n+6
2
Transcribed Image Text:To find centre of mais (CM) = [ @mse (dm) x Sdm • Susixie de CM = L f(x) dx CM CM 20 {x^"dx 20 L (2) j^x^ de dx (n+1) (n+2) { = (201²), " (n+1) (n+₂) 22+1 " 3L. 042 nyl x^ ? L (2) 4 (n+1) 4n+ 4 D stxatida suxndx 3L l So combining and O Lencai density at distance x from left end 3(x) = 20 (=) ² kg/m 3L BL 4 = 3 (n+2) = 3n+6 2
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