### Problem StatementGiven two particles with \( Q = 1.90 \, \mu C \) charges as shown in the figure below, and a particle with charge \( q = 1.36 \times 10^{-18} \, C \) at the origin. (Note: Assume a reference level of potential \( V = 0 \) at \( r = \infty \)).[Figure]- The figure shows a horizontal line representing the x-axis.- Two positive charges \( Q \) are located at positions \( x = -0.800 \, m \) and \( x = 0.800 \, m \) on the x-axis.- A positive charge \( q \) is located at the origin (0,0).### Questions#### (c) What is the electrical potential (in kV) at the origin due to the two \( 1.90 \, \mu C \) particles?**Answer:** \( 42.75 \, \text{kV} \) ✔\[\boxed{42.75 \, \text{kV}}\]#### (d) What If? What would be the change in electric potential energy (in J) of the system if the charge \( q \) were moved a distance \( d = 0.400 \, m \) closer to either of the \( 1.90 \, \mu C \) particles?**Answer:** \( 0 \, \text{J} \) ✘\[\boxed{0 \, \text{J}}\]

Answered: Image /qna-images/answer/12ee69e3-1ce4-4575-94e7-fbd6b7b56a06.jpg

Given two particles with Q = 1.90-µC charges as shown in the figure below and a particle with charge q = 1.36 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = o.) x = -0.800 m x = 0.800 m @ (c) What is the electrical potential (in kV) at the origin due to the two 1.90-µC particles? 42.75 kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 1.90-µC particles? X J

Given two particles with Q = 1.90-µC charges as shown in the figure below and a particle with charge q = 1.36 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = o.) x = -0.800 m x = 0.800 m @ (c) What is the electrical potential (in kV) at the origin due to the two 1.90-µC particles? 42.75 kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 1.90-µC particles? X J

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

### Problem Statement

Given two particles with \( Q = 1.90 \, \mu C \) charges as shown in the figure below, and a particle with charge \( q = 1.36 \times 10^{-18} \, C \) at the origin. (Note: Assume a reference level of potential \( V = 0 \) at \( r = \infty \)).

[Figure]
- The figure shows a horizontal line representing the x-axis.
- Two positive charges \( Q \) are located at positions \( x = -0.800 \, m \) and \( x = 0.800 \, m \) on the x-axis.
- A positive charge \( q \) is located at the origin (0,0).

### Questions

#### (c) What is the electrical potential (in kV) at the origin due to the two \( 1.90 \, \mu C \) particles?

**Answer:** \( 42.75 \, \text{kV} \) ✔

\[
\boxed{42.75 \, \text{kV}}
\]

#### (d) What If? What would be the change in electric potential energy (in J) of the system if the charge \( q \) were moved a distance \( d = 0.400 \, m \) closer to either of the \( 1.90 \, \mu C \) particles?

**Answer:** \( 0 \, \text{J} \) ✘

\[
\boxed{0 \, \text{J}}
\]

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