Two charges, 9₁ = −6,0 µCand q₂ = +3 µC are on x axis with the respective coordinates x₁ = 0 and x₂ = 12 cm. The electrical potential is set to 0 in the infinity. 91-6,0 μC = 21=0 92 = +3,0 μC x₂ = 12,0 cm 1. Show that the potential is given as: V(x) = q 4meo (1x₂-x₂/-1-3²1)

Two charges, 9₁ = −6,0 µCand q₂ = +3 µC are on x axis with the respective coordinates x₁ = 0 and x₂ = 12 cm. The electrical potential is set to 0 in the infinity. 91-6,0 μC = 21=0 92 = +3,0 μC x₂ = 12,0 cm 1. Show that the potential is given as: V(x) = q 4meo (1x₂-x₂/-1-3²1)

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Two charges, 91
-6,0 μC and 92
+3 μC are on x axis with the respective coordinates X₁ = 0
= 12 cm. The electrical potential is set to 0 in the infinity.
and X2
=
-6,0 μC
91=-
*1 = 0
=
92 +3,0 μC
=
x2 = 12,0 cm
1. Show that the potential is given as: V(x)
=
q
(1x2₂2²×₂1 — 12²₁1)

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