Given the reactions shown below, identify the reactant that is a. oxidized: b. reduced: c. reducing agent: d. oxidizing agent: Overall reaction: 2 AgNO3 + Cu →2 Ag+ Cu(NO3)2 Look closer at the oxidation half-reaction and the reduction half-reaction shown below: Ag+ + e Ag Cu Cu2+ + 2 e

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**Redox Reactions in Chemistry**

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Given the reactions shown below, identify the reactant that is:

a. **oxidized:**
   
b. **reduced:**
   
c. **reducing agent:**
   
d. **oxidizing agent:**

**Overall reaction:**

\[ 2 \text{AgNO}_3 + \text{Cu} \rightarrow 2 \text{Ag} + \text{Cu(NO}_3\text{)}_2 \]

**Look closer at the oxidation half-reaction and the reduction half-reaction shown below:**

\[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \]

\[ \text{Cu} \rightarrow \text{Cu}^{2+} + 2 e^- \]

**Explanation:**

- In the overall reaction, silver nitrate (\(\text{AgNO}_3\)) reacts with copper (\(\text{Cu}\)) to produce silver (\(\text{Ag}\)) and copper(II) nitrate (\(\text{Cu(NO}_3\text{)}_2\)). 
- The oxidation half-reaction shows silver ions (\(\text{Ag}^+\)) gaining an electron (\(e^-\)) to form silver (\(\text{Ag}\)). This indicates reduction as the silver ion gains an electron.
- The reduction half-reaction shows copper (\(\text{Cu}\)) losing two electrons to form copper ions (\(\text{Cu}^{2+}\)). This indicates oxidation as copper loses electrons.

From the reactions:

- The copper (\(\text{Cu}\)) is **oxidized** (loses electrons).
- The silver ion (\(\text{Ag}^+\)) is **reduced** (gains electrons).
- The substance that gets oxidized, copper (\(\text{Cu}\)), is the **reducing agent**.
- The substance that gets reduced, silver ion (\(\text{Ag}^+\)), is the **oxidizing agent**.

Fill in the blanks accordingly for practice and learning.

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Transcribed Image Text:--- **Redox Reactions in Chemistry** --- Given the reactions shown below, identify the reactant that is: a. **oxidized:** b. **reduced:** c. **reducing agent:** d. **oxidizing agent:** **Overall reaction:** \[ 2 \text{AgNO}_3 + \text{Cu} \rightarrow 2 \text{Ag} + \text{Cu(NO}_3\text{)}_2 \] **Look closer at the oxidation half-reaction and the reduction half-reaction shown below:** \[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \] \[ \text{Cu} \rightarrow \text{Cu}^{2+} + 2 e^- \] **Explanation:** - In the overall reaction, silver nitrate (\(\text{AgNO}_3\)) reacts with copper (\(\text{Cu}\)) to produce silver (\(\text{Ag}\)) and copper(II) nitrate (\(\text{Cu(NO}_3\text{)}_2\)). - The oxidation half-reaction shows silver ions (\(\text{Ag}^+\)) gaining an electron (\(e^-\)) to form silver (\(\text{Ag}\)). This indicates reduction as the silver ion gains an electron. - The reduction half-reaction shows copper (\(\text{Cu}\)) losing two electrons to form copper ions (\(\text{Cu}^{2+}\)). This indicates oxidation as copper loses electrons. From the reactions: - The copper (\(\text{Cu}\)) is **oxidized** (loses electrons). - The silver ion (\(\text{Ag}^+\)) is **reduced** (gains electrons). - The substance that gets oxidized, copper (\(\text{Cu}\)), is the **reducing agent**. - The substance that gets reduced, silver ion (\(\text{Ag}^+\)), is the **oxidizing agent**. Fill in the blanks accordingly for practice and learning. ---
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