Use the example for half reactions Cu(SO4) (aq) ++2Cu0Fe→ CuFe→ Fed+2(S)CuMoke all your decisions about redox based on changes in oxidation state.(s)+2Fe(50₂) (aq)+ (SO4)half-reaoundation and reduthat, taken togetheall electron rde domanBladKENHOwerkMLEO Goes GERF642PLose ElectronsOxidizedGain Electrons = Reduced Assign Oxidation States To All Elements:0Mg (s)022Cuo(s) + H₂ (8)002 (8)Fe₂O3 (s) + 3 CO (2)+1+5-2 0AgNO3(aq)+Li (s)→ MgO (s)0Cu (s)+1 -2H₂O(1)+1 +5-2→ LINO3(aq)Classify TheEquation0+ Ag (s)combustionsynthesisreaction+4-20single→ 3 CO₂ (4+ 2 Fe (s) displacementsingledisplacementreactionSingedisplacementreactionIdentify TheOXIDIZED ElementHALF REACTION:HALF REACTION:HALF REACTION:HALF REACTION:Identify TheREDUCED ElementHALF REACTION:HALF REACTION:HALF REACTION:HALF REACTION:Identify TheOXIDIZING Agent02CuoFe203 (s)AgNO3(aq)Identify TheREDUCING AgentMgH23 CO (g)Li (s)

Oxidation Loss of electron is oxidation. Reduction Gain of electron is reduction. Or Increase in…

Assign Oxidation States to All Elements: 0 Mg(s) + 0₂ (8) 2-2 Cuo + 0 H₂ (9) Fe₂O3(s) + 3 CO +1+5-2 AgNO3(aq) 0 MgO (s) Li (5) 0 → Cu (s) + +1 -2 H₂O) +1 +5-2 → LINO3(aq) +4-2 0 single → 3 CO₂ (4+ 2 Fe (s) displacement (8) + Equation 0 Ag (s) combustion synthesis reaction single displacement reaction Singe displacement reaction OXIDIZED Element HALF REACTION: HALF REACTION: HALF REACTION: HALF REACTION: REDUCED Element HALF REACTION: HALF REACTION: HALF REACTION: HALF REACTION: ONDIZIO 02 Cuo Fe203 (s) AgNO3 (aq) Mg H2 3 CO (g) Li (s)

Assign Oxidation States to All Elements: 0 Mg(s) + 0₂ (8) 2-2 Cuo + 0 H₂ (9) Fe₂O3(s) + 3 CO +1+5-2 AgNO3(aq) 0 MgO (s) Li (5) 0 → Cu (s) + +1 -2 H₂O) +1 +5-2 → LINO3(aq) +4-2 0 single → 3 CO₂ (4+ 2 Fe (s) displacement (8) + Equation 0 Ag (s) combustion synthesis reaction single displacement reaction Singe displacement reaction OXIDIZED Element HALF REACTION: HALF REACTION: HALF REACTION: HALF REACTION: REDUCED Element HALF REACTION: HALF REACTION: HALF REACTION: HALF REACTION: ONDIZIO 02 Cuo Fe203 (s) AgNO3 (aq) Mg H2 3 CO (g) Li (s)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

100%

Use the example for half reactions

Cu(SO4) (aq) +
+2
Cu
0
Fe
→ Cu
Fe
→ Fe
d
+2
(S)
Cu
Moke all your decisions about redox based on changes in oxidation state.
(s)
+2
Fe(50₂) (aq)
+ (SO4)
half-rea
oundation and redu
that, taken togethe
all electron r
de doman
BladKEN
H
Owerk
M
LEO Goes GER
F6
42
P
Lose Electrons
Oxidized
Gain Electrons = Reduced

Assign Oxidation States To All Elements:
0
Mg (s)
0
22
Cuo(s) + H₂ (8)
0
02 (8)
Fe₂O3 (s) + 3 CO (2)
+1+5-2 0
AgNO3(aq)
+
Li (s)
→ MgO (s)
0
Cu (s)
+1 -2
H₂O
(1)
+1 +5-2
→ LINO3(aq)
Classify The
Equation
0
+ Ag (s)
combustion
synthesis
reaction
+4-2
0
single
→ 3 CO₂ (4+ 2 Fe (s) displacement
single
displacement
reaction
Singe
displacement
reaction
Identify The
OXIDIZED Element
HALF REACTION:
HALF REACTION:
HALF REACTION:
HALF REACTION:
Identify The
REDUCED Element
HALF REACTION:
HALF REACTION:
HALF REACTION:
HALF REACTION:
Identify The
OXIDIZING Agent
02
Cuo
Fe203 (s)
AgNO3(aq)
Identify The
REDUCING Agent
Mg
H2
3 CO (g)
Li (s)

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