Given the QuickSort implementation from class, provide an 18-element list that will take the least number of recursive calls of QuickSort to complete. As a counter-example, here is a list that will cause QuickSort to make the MOST number of recursive calls: public static List input() { return Accaxs.asbist(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0); } And here's the QuickSort algorithm, for convenience: algorithm QuickSant Input: lists of integers 1st of size N Output: new list with the elements of 1st in sorted order if N < 2 return st pivot = lst[N-1] left = new empty list right = new empty list for index = 0, 1, 2, if lat[i]<= pivot left.add(lat[i]) else ... N-2 cight.add(lst[i]) return Quicksact(left) + [pivot] + QuiskSort (right)
Given the QuickSort implementation from class, provide an 18-element list that will take the least number of recursive calls of QuickSort to complete. As a counter-example, here is a list that will cause QuickSort to make the MOST number of recursive calls: public static List input() { return Accaxs.asbist(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0); } And here's the QuickSort algorithm, for convenience: algorithm QuickSant Input: lists of integers 1st of size N Output: new list with the elements of 1st in sorted order if N < 2 return st pivot = lst[N-1] left = new empty list right = new empty list for index = 0, 1, 2, if lat[i]<= pivot left.add(lat[i]) else ... N-2 cight.add(lst[i]) return Quicksact(left) + [pivot] + QuiskSort (right)
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![Q3 QuickSort
Given the QuickSort implementation from class, provide an 18-element list that will take the
least number of recursive calls of QuickSort to complete.
As a counter-example, here is a list that will cause QuickSort to make the MOST number of
recursive calls:
public static List<Integer> input() {
return Accaxsaslist(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0);
}
wwwwwww
And here's the QuickSort algorithm, for convenience:
algorithm QuickSart
Input: lists of integers 1st of size N
Output: new list with the elements of lat in sorted order
if N < 2
return st
pivot Jat[N-1]
left = new empty list
right = new empty list
for index = 0, 1, 2,
if lst[i]<= pivot
left.add(lat[i])
=
else
N-2
right add(lat[i])
return QuickSort(left) + [pivot] + QuickSort (right)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d009b7a-5e1c-499c-a434-821054b9abc8%2Fc7e9aa10-f9ed-4ca9-a16c-e88186e5cd8c%2Fidw9ggt_processed.png&w=3840&q=75)
Transcribed Image Text:Q3 QuickSort
Given the QuickSort implementation from class, provide an 18-element list that will take the
least number of recursive calls of QuickSort to complete.
As a counter-example, here is a list that will cause QuickSort to make the MOST number of
recursive calls:
public static List<Integer> input() {
return Accaxsaslist(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0);
}
wwwwwww
And here's the QuickSort algorithm, for convenience:
algorithm QuickSart
Input: lists of integers 1st of size N
Output: new list with the elements of lat in sorted order
if N < 2
return st
pivot Jat[N-1]
left = new empty list
right = new empty list
for index = 0, 1, 2,
if lst[i]<= pivot
left.add(lat[i])
=
else
N-2
right add(lat[i])
return QuickSort(left) + [pivot] + QuickSort (right)
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