Given the profile below determine: A) The length of the vertical curve needed to make the highest point on the vertical curve come exactly over the centerline of the cross road at station 150+ 7o. B) The vertical clearance between the profile grade on the vertical curve and the centerline of the cross road (h). Station of VPI 150+ 00.00 Elevation of VPI S0.00 m 3% +6% Cross-road Elevation 33.50 m Centerline of cross-road C) If the vertical clearance between the profile grade and the cross road is 5m Determine the station of cross road to BC ???

Q: An incoming grade of +1.800% meets an exiting grade of -2.500% at a PVI having station = 27+32.20…

A: Incoming grade = +1.800% Exiting grade = -2.500% PVI station = 27+32.20 PVI elevation = 231.87…

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: 3. Given a simple horizontal curve with A-8 00 00" and Pl at station 104450, calculate: a. R b. T d.…

A: a) Radius R = 1720 / D                    = 1720 /8                  = 215 m b) T = Radius x  tan…

Q: An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75%…

A:

Q: What is the length of the curve, G1, highest point of curve, and the elevation of the highest point…

A: To find : Length of the curve, G1, highest point of curve, and the elevation of the highest point on…

Q: angent grades of +2 on of 152 m above th th of the passing sig of the curve. (c) Co

A:

Q: An equal-tangent sag vertical curve on a section of a highway connects an initial grade of -2% and a…

A:

Q: An equal-tangent crest curve connects a +2.0% and a-1.0% grade. The PVC is at station + 670 and the…

A: The curve length will be: Lm=2×100station2 of PVI-station1 of PVCLm=200(1+790-1+670)      =240 ft

Q: 8, Horizontal Alignment Design - A horizontal curve has a deflection angle of 60 degree and a radius…

A: Radius of curve (R) = 300m Deflection angle (∆ or α) = 60°If the length of the curve is equal to…

Q: Sketch the graph of a symmetrical parabolic curve if it has descending grade of 4% and an ascending…

A: Answer Calculation of station of PC Since we are given symmetrical parabolic curve and symmetrical…

Q: Vertical summit curve has tangent grades of +1.5% and - 1.5% intersecting at station 4+000 at an…

A: Given- n1=+1.5%n2=-1.5%L=182

Q: An equal-tangent sag curve of length 920ft needs to be designed for 55 mph to connect an initial…

A: Given:- The length of the sag curve = 920 ft The design speed = 55 mph The initial downgrade = 5%…

Q: A vertical curve is to be design to joint (+3) percent grade with a (-3.5) percent grade, sight…

A: It is required to determine the minimum length of the curve. Assume S < L L=AS21002h1+2h22 Here A…

Q: The elevation of PT is at elevation 454.50m while the lowest point on the curve is located 40m from…

A:

Q: Question 3 An equal-tangent vertical curve is to be constructed between grades of -2 percent and +1…

A: Given :

Q: VERTICAL PARABOLIC CURVE IS TO CONNECT A BACK TANGENT OF -2% AND A FORWARD TANGENT OF 3%. THE CHANGE…

A:

Q: 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade…

A: Given: Sight Distance= 120 m  Grade lines intersection   Station = 9+000 Elevation = 160.50 m…

Q: A plus 2.8% grade elevation intersects a minus 5.1% grade at station 2 + 087.224 at an elevation of…

A:

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

A:

Q: A vertical parbolic curve was design in order to have a clear sight distance of 120 m . The grade…

A: sing relation for SSDSSD=vt+v22gf±Gf=0.35G=0.05t=2.5sec

Q: A grade ascending at the rate of 6% meets another grade descending at the rate of 4% at the vertex…

A: Given  G1= 6%  G2= -4 %

Q: 26.10 A grade of +1.5% intersects a grade of -2.5% at station of 1 + 080 of elevation 68.94 m. if…

A: Given Data:g1=1.5%g2=-2.5%station=1+080Elevation=68.94m

Q: curve is 10°. The curve has 7 intermediate stations between P.C. (10 + 300m) and P.T. After laying…

A: Given:- 5m full station curve=10 degree 7 intermediate stations  P.C.(10+300m) To find:- Compute all…

Q: You are required to set up a vertical curve for a highway alignment. Gradient of the backward and…

A: As per our guidelines we can solve one question only or the first three sub-parts only. If you need…

Q: between those two rc a. The required le b. Stationing and c. Location and el

A:

Q: Vertical highway curve: Given PVI at 128 + 00, L = 1,000 ft, g1 = -5%, g2 = +4%, and PVI elevation =…

A:

Q: A crest vertical curve (equal tangent) has PVI at station 210+00 and elevation 420.75 ft. The…

A: SPVI = Stationing of PVI = 210+00EPVI = Elevation of PVI = 420.75 ftg1 = Initial grade = 2.5% =…

Q: The tangent length of a simple horizontal curve is 1500.00 ft. The station of the point of…

A:

Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:- The initial grade of the curve = +1.512% The final grade of the curve = -1.785% The station…

Q: A 750-ft equal-tangent crest vertical curve connects tangents that intersect at elevation 572 ft.…

A:

Q: Q3/ Given the following vertical curve data: pvl at 19+00,L-500 ft g1=+2.5%, g2= -1% and elevation…

A: Given:- The stationing of point PVI = (19+00) The length of the curve = 500 ft The initial grade of…

Q: Problem A highway engineer must stake a symmetrical vertical curve where an entering grade of +0.80%…

A: Given : n1 = +0.80 % n2 = -0.40 % Station - 10 + 100 having an elevation = 140.36 m Allowable grade…

Q: Determine variables requested below for a horizontal curve with the following characteristics.…

A:

Q: Highway A merges with Highway B using a compound curve off-ramp. The point of compound curve is…

A:

Q: 1600 ft lomg equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft…

A: Position of tha loest curve x=Lvn12Nhere  Length of sag curve   Lv=1600 ftand   n1=3.5 %  and…

Q: 2. A VERTICAL PARBOLIC CURVE WAS DESIGN IN ORDER TO HAVE A CLEAR SIGHT DISTANCE OF 120 M THE GRADE…

A: Take L>SSDL=NS22H+2h2L=0.0812022×1.5+2×0.12L=242.6>S ok

Q: The minimum simple curve radius you recommended for a highway with design speed (96) Km/hr , super…

A: Given; V=96km/hr super elevation =5.50 f=0.11

Q: If PVI at sta 5+650 has an elevation of 122.45 m what is the elevation of the grade tangent at…

A: "Since you have asked multiple question, only first question will be solved for you. If you want any…

Q: A VERTICAL PARBOLIC CURVE WAS DESIGN IN ORDER TO HAVE A CLEAR SIGHT DISTANCE OF 120 M. THE GRADE…

A:

Q: C-A -3% grade is connected to a +4% grade for a vertical curve. The PC. station is 00 and PC.…

A:

Q: 3. A -4% grade line (400 ft length) intersects a -2% grade line (200 ft length) at station 63+00,…

A: Given:- The grade of line 1 (g1) = -4% The length of line 1 = 400 ft The grade of line 2 (g2) = -2%…

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.