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Given the power series n = 0 Find the Integral of the Power Series. 00 2 A, x2" dx = E A x(2n - 1) A n = 0 n = 0 00 00 B. Σ Α, x (2n - 1) .2n dx A n = 0 n = 0 x (2n + 1) Σ. 00 A 2n dx = n =0 2n 00 x(2n + 1) 00 D) ΣΑ, 2n dx = n = 0 n = 0 2n + 1 00 00 E x2" dx = E A (2n – 1) x(2n - 1) n = 0 n = 0

Given the power series n = 0 Find the Integral of the Power Series. 00 2 A, x2" dx = E A x(2n - 1) A n = 0 n = 0 00 00 B. Σ Α, x (2n - 1) .2n dx A n = 0 n = 0 x (2n + 1) Σ. 00 A 2n dx = n =0 2n 00 x(2n + 1) 00 D) ΣΑ, 2n dx = n = 0 n = 0 2n + 1 00 00 E x2" dx = E A (2n – 1) x(2n - 1) n = 0 n = 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the power series 00 2 A x2" n = 0 Find the Integral of the Power Series. Σ 00 A x2" dx = 2 A x (2n - 1) n = 0 n = 0 Σ B .2n dx = 2 A 2n x(2n - 1) A n = 0 n = 0 00 (2n + 1) E A, 2n A. n = 0 dx = n = 0 2n 00 x (2n |dx = 2 A + 1) 00 E A, n = 0 n = 0 2n + 1 00 E dx =Σ Α A (2n – 1) x(2n - 1) n = 0 n = 0
Transcribed Image Text:Given the power series 00 2 A x2" n = 0 Find the Integral of the Power Series. Σ 00 A x2" dx = 2 A x (2n - 1) n = 0 n = 0 Σ B .2n dx = 2 A 2n x(2n - 1) A n = 0 n = 0 00 (2n + 1) E A, 2n A. n = 0 dx = n = 0 2n 00 x (2n |dx = 2 A + 1) 00 E A, n = 0 n = 0 2n + 1 00 E dx =Σ Α A (2n – 1) x(2n - 1) n = 0 n = 0
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