Given the following two half-reactions, write the overall reaction in the direction in which it is product- favored, and calculate the standard cell potential. Pb2*(aq) + 2 e¯ → Pb(s) E° = -0.126 V Fe3*(aq) + e¯ → Fe2*(s) E° = +0.771 V A Pb?*(aq) + 2 Fe²*(s) → Pb(s) + 2 Fe³*(aq); 'cell = +0.897 V B Pb2*(aq) + Fe²*(s) → Pb(s) + Fe³*(aq); cell = +0.645 V (©) Pb(s) + 2 Fe3*(aq) → Pb²*(aq) + 2 Fe²*(s); * cell = +1.416 V D Pb(s) + 2 Fe³*(aq) → Pb²*(aq) + 2 Fe²*(s); 'cell = +0.897 V Pb(s) + Fe³*(aq) → Pb²*(aq) + Fe²*(s); F. cell = +0.645 V
Given the following two half-reactions, write the overall reaction in the direction in which it is product- favored, and calculate the standard cell potential. Pb2*(aq) + 2 e¯ → Pb(s) E° = -0.126 V Fe3*(aq) + e¯ → Fe2*(s) E° = +0.771 V A Pb?*(aq) + 2 Fe²*(s) → Pb(s) + 2 Fe³*(aq); 'cell = +0.897 V B Pb2*(aq) + Fe²*(s) → Pb(s) + Fe³*(aq); cell = +0.645 V (©) Pb(s) + 2 Fe3*(aq) → Pb²*(aq) + 2 Fe²*(s); * cell = +1.416 V D Pb(s) + 2 Fe³*(aq) → Pb²*(aq) + 2 Fe²*(s); 'cell = +0.897 V Pb(s) + Fe³*(aq) → Pb²*(aq) + Fe²*(s); F. cell = +0.645 V
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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see the photo.
![Given the following two half-reactions, write the overall reaction in the direction in which it is product-
favored, and calculate the standard cell potential.
Pb2*(aq) + 2 e- → Pb(s)
E° = -0.126 V
Fe3*(aq) + e- → Fe2*(s)
E° = +0.771 V
000
Pb?*(aq) + 2 Fe²*(s)
Pb(s) + 2 Fe*(aq);
сеll
= +0.897 V
Pb2*(aq) + Fe2*(s) → Pb(s) + Fe*(aq);
= +0.645 V
cell
Pb(s) + 2 Fe*(aq) → Pb²*(aq) + 2 Fe²*(s);
= +1.416 V
'cell
Pb(s) + 2 Fe³*(aq) → Pb²*(aq) + 2 Fe²*(s); p
cell
= +0.897 V
E
Pb(s) + Fe³*(aq) → Pb²*(aq) + Fe²*(s);
= +0.645 V
cell](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb15f243-43d5-4c4e-b033-c0fbd2cde13c%2F598a2569-b007-444b-89fe-8417c2f814d6%2Fk3fo1wa_processed.png&w=3840&q=75)
Transcribed Image Text:Given the following two half-reactions, write the overall reaction in the direction in which it is product-
favored, and calculate the standard cell potential.
Pb2*(aq) + 2 e- → Pb(s)
E° = -0.126 V
Fe3*(aq) + e- → Fe2*(s)
E° = +0.771 V
000
Pb?*(aq) + 2 Fe²*(s)
Pb(s) + 2 Fe*(aq);
сеll
= +0.897 V
Pb2*(aq) + Fe2*(s) → Pb(s) + Fe*(aq);
= +0.645 V
cell
Pb(s) + 2 Fe*(aq) → Pb²*(aq) + 2 Fe²*(s);
= +1.416 V
'cell
Pb(s) + 2 Fe³*(aq) → Pb²*(aq) + 2 Fe²*(s); p
cell
= +0.897 V
E
Pb(s) + Fe³*(aq) → Pb²*(aq) + Fe²*(s);
= +0.645 V
cell
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