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Given the following thermochemical equations: ... AH° = -116 kJ AH° = -256 kJ 2NO) + 02(9) → 2NO2) 2N2(9) + 502(9) + 2H201) → 4HNO3(aq) N2) + O2c®) → 2NO(g) Calculate the enthalpy (in Joule) for this reaction: AH° = 183 kJ 3NO2(G) + H20(1) → 2HNO3(aq) + N0) Enter your answer below (one decimal place and do not put the unit) Round your answer to 1 decimal place.

Given the following thermochemical equations: ... AH° = -116 kJ AH° = -256 kJ 2NO) + 02(9) → 2NO2) 2N2(9) + 502(9) + 2H201) → 4HNO3(aq) N2) + O2c®) → 2NO(g) Calculate the enthalpy (in Joule) for this reaction: AH° = 183 kJ 3NO2(G) + H20(1) → 2HNO3(aq) + N0) Enter your answer below (one decimal place and do not put the unit) Round your answer to 1 decimal place.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Given the following thermochemical equations: ... 2NOG) + 02(9) → 2NO2(G) 2N29) + 502(g) + 2H20() → 4HNO3(aq) N2E) + 02(g) → 2NO(g) Calculate the enthalpy (in Joule) for this reaction: AH° = -116 kJ AH° = -256 kJ AH° = 183 kJ 3NO2(g) + H20) → 2HN03(aq) + N0(g) Enter your answer below (one decimal place and do not put the unit) Round your answer to 1 decimal place.
Transcribed Image Text:Given the following thermochemical equations: ... 2NOG) + 02(9) → 2NO2(G) 2N29) + 502(g) + 2H20() → 4HNO3(aq) N2E) + 02(g) → 2NO(g) Calculate the enthalpy (in Joule) for this reaction: AH° = -116 kJ AH° = -256 kJ AH° = 183 kJ 3NO2(g) + H20) → 2HN03(aq) + N0(g) Enter your answer below (one decimal place and do not put the unit) Round your answer to 1 decimal place.
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