Given the following: Solutions 0.04 M KI 1% starch 0.03 M Na2S2O3 0.05 M H₂SO4 0.08 M NaCl and Solutions 0.04 M H2O2 deioinized water Flask 1 25.0 mL 5.00mL 5.50 mL 5.00 mL O O Rate=k[I][H₂O₂] Beaker 1 25.0 mL 0 Calculate the following for each run: • the initial molarities of I and H₂O2 (from the solutions tables) • the rates of reaction [12]/time (calculate the [1₂] from [S₂O32-] and the reaction: 12(aq) + 2 S₂03² (aq) → 21 (aq) +S406² (aq) Choose the correct rate law for this reaction from your calculations. O Rate=k{1]2[H₂O₂] Rate=k[I][H₂O₂]² O Rate=k[1]²[H₂O₂]² Flask 2 25.0 mL 5.00mL 5.50 mL 5.00mL 0 Beaker 2 12.5 mL 12.5 mL Following the procedure Run 1 is when Beaker 1 is added to Flask 1 and the timer is started giving the time recorded for the run in the table below. This is repeated with Beaker 2 and Flask 2 for Run 2 and finally Beaker 3 and Flask 3 for Run 3: The results for these runs are given below: Run Time (seconds) 1 35 2 66 3 72 Flask 3 12.5 mL 5.00mL 5.50 mL 5.00mL 10.0 mL Beaker 3 25.0 mL 0

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Given the following:
Solutions
0.04 M KI
1% starch
0.03 M Na2S2O3
0.05 M H₂SO4
0.08 M NaCl
and
Solutions
0.04 M H2O2
deioinized water
Flask 1
25.0 mL
5.00mL
5.50 mL
5.00 mL
O
O Rate=k[I][H₂O₂]
Beaker 1
25.0 mL
0
Calculate the following for each run:
• the initial molarities of I and H₂O2 (from the solutions tables)
• the rates of reaction [12]/time (calculate the [1₂] from [S₂O32-] and the reaction:
12(aq) + 2 S₂03² (aq) → 21 (aq) +S406² (aq)
Choose the correct rate law for this reaction from your calculations.
O Rate=k{1]2[H₂O₂]
Rate=k[I][H₂O₂]²
O Rate=k[1]²[H₂O₂]²
Flask 2
25.0 mL
5.00mL
5.50 mL
5.00mL
0
Beaker 2
12.5 mL
12.5 mL
Following the procedure Run 1 is when Beaker 1 is added to Flask 1 and the timer is started giving the time recorded for the run in the table below. This is repeated with Beaker 2 and Flask 2 for Run 2 and
finally Beaker 3 and Flask 3 for Run 3:
The results for these runs are given below:
Run Time (seconds)
1
35
2 66
3
72
Flask 3
12.5 mL
5.00mL
5.50 mL
5.00mL
10.0 mL
Beaker 3
25.0 mL
0
Transcribed Image Text:Given the following: Solutions 0.04 M KI 1% starch 0.03 M Na2S2O3 0.05 M H₂SO4 0.08 M NaCl and Solutions 0.04 M H2O2 deioinized water Flask 1 25.0 mL 5.00mL 5.50 mL 5.00 mL O O Rate=k[I][H₂O₂] Beaker 1 25.0 mL 0 Calculate the following for each run: • the initial molarities of I and H₂O2 (from the solutions tables) • the rates of reaction [12]/time (calculate the [1₂] from [S₂O32-] and the reaction: 12(aq) + 2 S₂03² (aq) → 21 (aq) +S406² (aq) Choose the correct rate law for this reaction from your calculations. O Rate=k{1]2[H₂O₂] Rate=k[I][H₂O₂]² O Rate=k[1]²[H₂O₂]² Flask 2 25.0 mL 5.00mL 5.50 mL 5.00mL 0 Beaker 2 12.5 mL 12.5 mL Following the procedure Run 1 is when Beaker 1 is added to Flask 1 and the timer is started giving the time recorded for the run in the table below. This is repeated with Beaker 2 and Flask 2 for Run 2 and finally Beaker 3 and Flask 3 for Run 3: The results for these runs are given below: Run Time (seconds) 1 35 2 66 3 72 Flask 3 12.5 mL 5.00mL 5.50 mL 5.00mL 10.0 mL Beaker 3 25.0 mL 0
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