Given the following reaction, the equilibrium constant, and the initial concentrations; answer the four bullet questions. 2 NO2 (e) = 2 NO (g) O2 (g) Kc = 1.56 x 10-10 Initial Species Concentration (M) NO2 5.62 x 10-10 NO 3.99 x 10-16 O2 9.35 x 10-3 Set up the equilibrium expression, and calculate the reaction quotient (Q). Note: ^ means "to the" Q = [ Select ] • How does Q compare to K? Q is [ Select ]

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Chapter1: Chemical Foundations
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Both boxes. 
box 2 answer choices: Q is less than K, Q is greater than K, Q is equal to K.

Given the following reaction, the equilibrium constant, and the
initial concentrations; answer the four bullet questions.
2 NO2 (g) = 2 NO (g) + O2 (g)
K 1.56 x 10-10
Initial
Species Concentration
(M)
NO2
5.62 x 10-10
NO
3.99 x 10-16
O2
9.35 x 10-3
• Set up the equilibrium expression, and calculate the reaction
quotient (Q). Note: ^ means "to the"
[ Select ]
%3D
• How does Q compare to K?
Q is
[ Select ]
K.
Transcribed Image Text:Given the following reaction, the equilibrium constant, and the initial concentrations; answer the four bullet questions. 2 NO2 (g) = 2 NO (g) + O2 (g) K 1.56 x 10-10 Initial Species Concentration (M) NO2 5.62 x 10-10 NO 3.99 x 10-16 O2 9.35 x 10-3 • Set up the equilibrium expression, and calculate the reaction quotient (Q). Note: ^ means "to the" [ Select ] %3D • How does Q compare to K? Q is [ Select ] K.
• Set up the equilibrium expression, and calculate the reaction
quotient (Q). Note: ^ means "to the"
= v[ Select]
2.12 x 10^14
How d
4.41 x 10^-17
4.71 x 10^-15
1.51x10^8
Q is
6.64 x 10^-9
Transcribed Image Text:• Set up the equilibrium expression, and calculate the reaction quotient (Q). Note: ^ means "to the" = v[ Select] 2.12 x 10^14 How d 4.41 x 10^-17 4.71 x 10^-15 1.51x10^8 Q is 6.64 x 10^-9
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We are given the initial concentrations of reactants and products , we have to find the reaction quotient.

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